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GCSE AQA Chemistry higher tier C3: Quantitive Chemistry Questions & Answers $12.49   Add to cart

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GCSE AQA Chemistry higher tier C3: Quantitive Chemistry Questions & Answers

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  • Course
  • GCSE AQA Chemistry higher
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  • GCSE AQA Chemistry Higher

What is Avogadro's constant? - ANSWERS1 mole = 6.02 x 10^23 atoms What is equation for moles? - ANSWERSMoles = mass/Mr How would you use molar mass to balance an equation? - ANSWERS1) Dive the mass by the Mr to calculate the number of moles of each. 2) Dive each number of moles by the smalle...

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  • November 18, 2024
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  • Exam (elaborations)
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  • GCSE AQA Chemistry higher
  • GCSE AQA Chemistry higher
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GCSE AQA Chemistry higher tier C3:
Quantitive Chemistry Questions &
Answers
What is Avogadro's constant? - ANSWERS1 mole = 6.02 x 10^23 atoms

What is equation for moles? - ANSWERSMoles = mass/Mr

How would you use molar mass to balance an equation? - ANSWERS1) Dive the mass
by the Mr to calculate the number of moles of each.
2) Dive each number of moles by the smallest to determine the ratio.
3) The molar ratio is equal to the coefficient in the equation.

How much is 1 dm^3 in cm^3?
How much is 1 dm^3 in ml^3? - ANSWERS1 dm^3 = 1000cm^3
1 dm^3 = 1000ml^3

What is the equation for concentration using quantity of solute? -
ANSWERSConcentration ( g/dm^3) = Quantity of solute (g) / volume ( dm^3)

What is the equation for concentration using moles? - ANSWERSMoles ( mol) =
concentration ( mol/dm^3) * Volume (dm^3)

What are the steps to get full marks in a Titration calculation finding concentration? -
ANSWERS1) Write down any know values ( either concentration, volume or find moles
using mass/ Mr)
2) Calculate moles using Moles = Mass / Mr
3) Use the mole ratio to calculate the number of moles ( mol ratio * moles)
4) Use equation to find concentration mol/volume = concentration

What is percentage yield? - ANSWERSAmount of product actually made as a % of the
amount you should theoretically make.

What is the equation for percentage yield? - ANSWERSactual yield/theoretical yield x
100

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