-.75 -.50 x a hundred and twenty - ANS-The patient's RX is -1.Seventy five -.50 x one hundred
twenty with a +2.00 add preferred trifocal. What is the power via the intermediate.
A. -1.25 -.50 x 120
B. -.Seventy five -.50 x one hundred twenty
C. -.75 -.50 x 30
D. -1.00 -.50 x 150
-0.50 - ANS-The round equal of the lens +1.00 -3.00 x90 is
A. +zero.50
B. -zero.50
C. +1.25
D. -1.25
-zero.50 -2.50 x115 - ANS-Which RX of the subsequent is the same as the subsequent RX:
-three.00 +2.50 x25
A. -3.00 +2.50 x105
B. -zero.50 -2.50 x115
C. +zero.50 +2.50 x115
D. +3.00 -zero.50 x105
-2.00 -1.00 x90 - ANS-The optician has simply neutralized an unknow electricity lens with check
lenses. The check lens used to neutralize the energy in the vertical is a plus 2.Zero and the
check lens used to neutralize the electricity inside the horizontal is a plus 3.00. What is the RX?
-2.00 +zero.50 x180
-2.00 -1.00 x 90
-1.50 -zero.50 x 180
+1.00 +zero.50 x180
-three.25 -1.50 x180 - ANS-If your lensometer reads +0.25 and not using a lens, a lens that
measures -three.00 -1.50 x180 is actually
A. -2.75 -1.25 x180
B. -2.Seventy five -1.50 x180
C. -three.25 -1.Seventy five x180
D. -3.25 -1.50 x180
-9.50 - ANS-A affected person refracted at 15mm is prescribed a -10.00 shpere. The dispenser
finds that the real becoming distance might be at 10mm. What must the compensated lens
energy be?
A. -nine.50
B. -nine.Seventy five
C. -10.75
D. -10.50
+1.00 -1.25 - ANS-In neutralizing a lens of unknown energy your first reading is +1.00 and the
next reading that focuses the cylinder goal is -zero.25.
, What is the RX?
A. +1.00 -zero.25
B. -0.25 +2.00
C. +1.00 -1.25
D. +zero.25 +2.25
+1.75 -.25 x90 - ANS-What might the reading RX be if the subsequent distance RX and bifocal
addition are given:
A. +.50 -.25 x90
B. +1.75 -.25 x90
C. +2.75 -.25 x90
D. +1.25 -.25 x90
+2.00 -2.00 x90 - ANS-Which of the following has no power in the one hundred eighty degree
median?
A. +2.00 -2.00 x90
B. +2.00 +2.00 x180
C. +1.00 +1.00 x135
D. +1.00 -2.00 x45
+2.50 - ANS-If the RX is OS +1.00 +3.00 x45, what might be the full power at axis power
ninety?
A. +1.00
B. +2.00
C. +2.25
D. +2.50
+6.12/+eight.12 - ANS-When verifying an upload on on a 1 piece bifocal with a lens clock, a
+2.00 upload would clock ____
in the distance and ______ in the section.
A. +6.12/+eight.12
B. +4.50/-7.25
C. +four.37/+7.12
D. +three.Seventy five/+1.00
1 diapter - ANS-Determine imbalance at the reading degree within the following prescription
(10mm reading intensity)
OD: -4.00 -2.00 x90 OS: -1.00 -3.00 x180
A. 4 diapters
B. 2 diapters
C. 1 diapter
D. No imbalance
1 diapter base in prism - ANS-A +2.00 diopter lens decentered in 5mm beyond the sufferers
measured pd will create
A. 1 diapter base out prism
B. 2 diapters base out prism
C. 1 diapter base in prism
D. 2 diapters base in prism
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