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physics 1 lab -free fall

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The notes for the physics lab on free fall focus on studying the motion of objects under the influence of gravity alone. Key concepts include acceleration due to gravity (g), equations of motion, and the absence of air resistance. The lab involves measuring the time and displacement of a falling ob...

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  • December 26, 2024
  • 2
  • 2023/2024
  • Class notes
  • Holler
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bernadinegurning1
tall
lab 3 : free
·

models for graphs ·

procedure lab 4
·
model used to compare (time , position) data points at constant acceleration obtain a conversion factor of aubins to meters

X =
Xo + Vot +
Gat 9 = 9 8 m/s
.




equation rewritten in y mx + b format
4 aub Is 2
·
=
9 best = 291 .




v =
Vo + at

9
.8 m Xaubins2914
abso n
you can use this equation when obtaining X (position) a + (time) data to plot .




S2
a velocity vs .
time graph

Vo = intercept 29
.7 3 0 aubins per meter

d =
slope
291 4 aubins
X meters.
a
a
.




.




·

question 2 S2

·


graph for x vs .
t of a free falling object . .
0 034 meters per aubin


Xa A

as time
I ncreases the position ,




of the object relative to its

starting point increases

D
↳ the curve of the graph represents the
t
velocity of the object which is also increasing

as the object falls

velocity intercept : Initial position
Slope :
question 3
,
·




graph of v vs t
·



.




va
* Obtain velocity by v =

E
T
velocity increases as time increases due to gravity

↳ the line represents gravitational

acceleration which is constant

slope : gravity intercept : initial velocity
#
,




·
trendline equation

y = mx + b

X: independent variable

y : dependent variable


·

question 5
meaning of intercept a slope

. 3046 represents the acceleration in mis
?
m = 2


b = 3 3029 represents the initial velocity i n mis
.




* when an uncertainty is greater than the central value , It implies that the

quantity is consistent wi ze ro


eg : (0 .
07 = 0 .
09) mis


procedure
·




uncertainty in Av


v =

E
·
uncertainty of X = 0 .
05



· WemultipliedXb S s



? AV =

30AX +
1 x I . (0 05
30 .
+ 0 .
05) = 3

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