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Uitgewerkte oplossingen WZ1-3 conceptuele natuurkunde, HIR(B) $6.95
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  3. Katholieke Universiteit Leuven (KU Leuven)
  4.  
  5. Bachelor Handelsingenieur
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  7. Conceptuele natuurkunde met technische toepassingen (D0H21A)

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Uitgewerkte oplossingen WZ1-3 conceptuele natuurkunde, HIR(B)

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  • Course
  • Conceptuele natuurkunde met technische toepassingen (D0H21A)
  • Institution
  • Katholieke Universiteit Leuven (KU Leuven)

Dit document omvat alle opgaves en uitgewerkte oplossingen (excl Z.3.10) van werkzittingen 1-3 van het vak 'conceptuele natuurkunde met technische toepassingen'.

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Document information

  • January 2, 2025
  • 8
  • 2024/2025
  • Other
  • Unknown

Subjects

  • vectoren
  • kinematica
  • dynamica
  • energie
  • impuls
  • arbeid

Written for

  • Katholieke Universiteit Leuven (KU Leuven)
  • Bachelor Handelsingenieur
  • Conceptuele natuurkunde met technische toepassingen (D0H21A)
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WZ 1: vectoren, vectorrekenen en kinematica

·




5350
&
· ---- B
tan (35 % =

Too
( x = 70
. 02m



-
2




-




(m ,, y ,) =
70 ;
-
3
,
5)



o
&
(22 , y2) :




·in
(
Dy
= 4
, 1 (m2 Ya) ,
= (7 ,
10
;
-
3 5
,
+ 4
,
1)


b = 7, =
(7, 10 j
·

0
. 6)
27


(23 %3) (Ma 43) ,
= (7 ,
10 -
15
; 0
,
60) =
(17 ,
9 ; 0. 60
y2)
,

(n2 ,

------------------


O
&
⑧ - 7
2
- = -
7
, 9 n + 0
. 6 y




·
I602 + 0
.
= 7 ,
92 m




tan(v)
== 4
,
340 ten Noorden v We he




- - -


2 as




~ s
-N
(y -
as)
·
cos(30 %
= y = 39




-
Sin (30
=
·

n = 20

wi


- 2




/
O

(n as) -




= -
2300 ex + 3984 g + 2450e
↳ Z

(1 =
200 39842 24502
2
+ + =
5212




-




En e
zo




(-3 yey
-
+ xe n + 2ey +
yez) =
-




= = 3x -


Ge



-




S n-component :
Ex =
Vox + axt



y-component :
Vy =
Va+ aut




S
0 =
-
14 + 67


=
Sat
taxt (7)
7 37 +
=
+ =
Ma +
·
x
7
=

7
=
= 0 -
14 -
+ -

6 .



= -
13 3 0 -
= +
,




Voxt taxt 7
z +-3(7) 8
·
y yo + + 0 + = 2
-
-
= =
-




,




Dus : = mex +
yex = =
16 , 3 -
5 , 2 ey



#
-ook
= 200 = smans e n




(t) x = t Vanto = 200s .



25m/s = 5000 m = 5
,
0 km

, (a) Er geldt :
x-richting : constant =
ax = 0



w y-richting : a constant en




indienbeweging mithen een
Vox = o




S S
+
opsplitsen i n m 20 Voxt +
+ a 20 VoxtQ
= + n =
+
,


componenten :


(7)

y =
yo +
Vat - gt2 y =
y0
-




7gt2




S
(e) x = no + Vat +
taxta n a h ou re l tijd op hoogte 0
,
65m :




V
+ gt
10 060
45-7
yo Voyt . 65 2
y = + 0
-
=
-
= =
,




① invullen in & : 15 = 0 + Vox 0 ,
6 1 v = 25m/S




S
u =
Voxt &


y =
yo - gt


7 (c)t
n a hourel tijd op de grand : 0 = 2 ,
45-10t-t = 0
.
= 0
.
7s



③ invullen in : n = 25 .
0
,
7 = 17 ,
5 m




17 5-15 2 57 b a l landt i n het
,
=
, = juiste vak


:
Y

----------
sino coördinaten schip :




2
15

-
e ·un
7
n n




S S
kustwacht Max (40)
Voxt
tax 50 in Voxt
taxt
Mo + + 5 18 26 cir
schip Max
=
: = : = Ko + + =
,
+ ·




5000 20(40 % 7
tayz t 2
19 . 32 26
Yay Voxt +ay + +
yo + + =
Ysx y0 +
Voxt + =
.

-
= =




Op onderscheppingspunt geldt :




·

Uw
·
=
Msx Yny =
Y3

= 50 sin (b) + = 5
,
18 + 26 sin (40 % + ( 50 Los(0) + = 19 , 32 + 26 ·


cos(40 % +


t 1, e
in (0)
*+
19 9 2
= coslo 1
↳ 7)
32+
= , ,




Sind + costu = 1



224172 173 16567 396 , 806472 + 769 , 70887
24
= 279 ,
+ ,
+ 52624
+
= 1
2
250072 2500 +



7 ) 1823 9695 + 942 82447 + 400 0948 = 0
, , ,




D = 3807960 ,
698




-
Dus :

tag
sin(o): = 27
,
70 ten ooten ulh Noord e




S taxt
n =
no + Wxt +




y y0 + wy +
+g+
-
=




87

S
m
n = Vo ·




cos(40 % +

7)

y yo + wo in(40 % +
-gt
-

=




S
[ t =


Castroo
3 , 05 2 + 5. in (90 %+
+ gt
-
=




Ee
7 , 341
%
m
·
= 7
105 (40 Wo 10

cuo
in 9 . 81 ( #
=

= V . ,


ontrol

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