bnu1501 assignment 03 semester 02 2020 questions and suggested solutions
bnu1501 assignment 03 semester 02 2020
bnu1501 assignment 03 semester 02
bnu
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University of South Africa (Unisa)
BNU1501 - Basic Numeracy (BNU1501)
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Basic Numeracy
BNU1501
Semesters 1 and 2
Department of Decision Sciences
Assignment 3: 2020
Semester 2
Due Date: 2 September 2020
Unique Number: 858213
Before answering the assignment questions, please work through the
following study material:
• Chapters 4, 5 and 6
Question 1 and 2 are based on the following information. Consider the figure below, which is a
combination of half circles, a rectangle and triangles.
Question 1
Calculate the perimeter of the figure, in meters, and round off your answer to two decimal digits.
[1] 1.03m
, [2] 7.14m
[3] 0.71m
[4] 71.42m
Answer:
Perimeter (P) The distance around the outside of a shape (sum of all sides)
Rectangle C = 2 (l + w)
Square C=4l
Triangle C=a+b+c
Circle C = 2 π^r
Irregular figures: The perimeter is simply the sum of the lengths of all the sides.
Given: A circle with r = 10cm.
The circumference is calculated as
𝐶 = 2𝜋𝑟
= 2×𝜋 ×5
≈ 31,42
The circumference of the circle is 31,42cm.
𝐶 = 10𝑐𝑚 + 10𝑐𝑚 + 31,42𝑐𝑚 + 10𝑐𝑚 + 10𝑐𝑚 = 71,42𝑐𝑚
71,42 cm to m:
We know that 100cm = 1m.
Therefore
71,42
71,42𝑐𝑚 = = 0,71𝑚
100
71,42𝑐𝑚 is equal to 0,71𝑚
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