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Antwoorden Systematische natuurkunde havo 4 Noordhoff (9de druk) deel 4 $4.58   Add to cart

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Antwoorden Systematische natuurkunde havo 4 Noordhoff (9de druk) deel 4

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zie omschrijving bundel systematische natuurkunde

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  • November 13, 2020
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  • 2020/2021
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Antwoorden opgaven les 4 Fysica
Opgave 20
a Voor alle momenten geldt: M = F · r.
F en r bepaal je in figuur 4.34 van het basisboek.

F1 = 15 N
r1 = 0 m
M1 = 15  0
M1 = 0 N m

F2 = 20 N
r2 = 2,0 m
M2 = 20  2,0
M2 = 40 N m

F3 = 15 N
r3 = 1,0 m
M3 = 15  1,0
M3 = 15 N m

F4 = 30 N
r4 = 1,5 m
M4 = 30  1,5
M4 = 45 N m
b M1: er is geen moment: geen draaiing
M2: draaiing rechtsom
M3: draaiing linksom
M4: draaiing linksom



Opgave 22
a A: as van de trommel
B: as van de trommel
D: scharnierpunt van het brugdek
b A: linksom
B: linksom
D: linksom
c Voor een moment geldt: M = F · r.
Het moment in B is gelijk aan het moment in A.
De arm van het moment in A is groter dan de arm van het moment in B.
De kracht in A is dus kleiner dan de kracht in B.
Dus de spierkracht is kleiner dan de kracht die de trommel op de kabel uitoefent.
d Voor een moment geldt: M = F · r.
De kracht in B is gelijk aan de kracht in D.
De arm van de kracht in D is groter dan de arm van de kracht in B.
Het moment in D is dus groter dan het moment in B.

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