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Oefentoets H1 Logaritmische functies 5vwo (moderne wiskunde) $4.40   Add to cart
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Oefentoets H1 Logaritmische functies 5vwo (moderne wiskunde)
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  • Course
  • Wiskunde B
  • Level
  • VWO / Gymnasium

Dit is een oefentoets om je voor te bereiden op de toets van: Hoofdstuk 1 Logaritmische functies , moderne wiskunde 5 vwo wiskunde B. Dit document bevat toets vragen + uitwerkingen

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Document information

  • November 17, 2020
  • 3
  • 2019/2020
  • Exam (elaborations)
  • Questions & answers

Subjects

  • moderne wiskunde
  • logaritmische functies
  • logaritme
  • 5 vwo
  • oefentoets h1
  • wiskunde b
  • oefentoets

Written for

  • Secondary school
  • VWO / Gymnasium
  • Wiskunde B
  • 5
All documents for this subject (269)

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Oefentoets H1 Logaritmische functies V5 WB
Rond eventueel af op twee decimalen.

1 Los de onderstaande vergelijkingen exact op.
(2) a. 4 + x 8=9
7
(3) b. 4 ∙ ❑ log ( 2−x ) −3=5
(4) c. Geef je antwoord in de vorm x=a+ b ❑c log ( d )
2+3 ∙5 x =127
6 6 6 6
(4) d. 2 ∙ ❑log ( 2 ) +2 ∙ ❑ log ( 5+ x ) =❑log (1−x )+ ❑log ( 4 )

1
2 Gegeven is de functie f ( x )=4+ 3∙ 2 log ( x−8 )
❑
(3) a. Geef exact het domein, bereik, asymptoot. Licht je antwoord toe.
(3) b. Bereken exact de snijpunten met de assen.
(5) c. Los exact op: f (x) ≥10.
(3) d. Druk x uit in y.

3 Losse formules
2
(3) a. Herschrijf de formule g ( x )=❑4log ( 9 x )+ ❑2log (7 ) in de vorm g ( x )=❑log ( a x b ).
(3) b. Druk p uit in q.
3
4 q+1=5∙ ❑log ( 4 p )
6
P b
(3) c. Herschrijf naar de vorm q= log
❑ a ( )
6 6 6
6 q=log ❑( 4 ) +¿ log ❑( p )−¿ ❑ log ( 152 ) ¿ ¿
3
(3) d. Bereken het maximum van de formule n ( x )=1+2 ∙ ❑ log ( 5 x−4−x2 )



4 Voor de geluidsterkte D in decibel (dB) van een toongenerator geldt:
❑
4,9 ∙ 105
D=10 ∙ log
❑
( r2 )
Hierin is r de afstand in meters tot de generator.
(1) a. Bereken de geluidsterkte op een afstand van 25 meter.
(3) b. Bereken algebraïsch op welke afstand de geluidsterkte meer dan 36 dB is.
(3) c. De formule is te herleiden tot de vorm D=a+b ∙ log r.
Bereken de waarde van a en B

Einde van de toets
Normering onder voorbehoud
pnt
cijfer= ∗9+ 1
46

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