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All Solutions for Gasturbine Performance Year 2 Aviation Engineering
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Gasturbinesperformance Questions
,Week 3 Turbojet
OQ 8. 2.1
I =
15°C = 288 A. Vs .
A, =
f- Vz -
Az
V, = 315 mis 4,5 =
Pa -
Vz Az .
Pz = 1.35bar Pz
Vz =
46 mis Pz =
=
Ín =
4,5kg IS VI -
VI 3152 -
462
Tz Is
=
288 -1 336,313
9/1 Kg t
-
=
( K)
-
p = 1005 .
=
2. (p 2- 1005
R
287911kg K)
= '
g. =
1135.1051-2
B-
.
R
=
336,313.287
=
1,398647
in 4,5
Az =
0.6994
-
= =
-
B. Vz 1398647 .
46
1 -
d =
Wto =
0,298 m
OQ 8. 2.2 .
17=0.80 bar W= -
Dho = -
Dh -
DER
Tr = 10 °C =
283K
Pz = 5,5bar W= -
ni ( .
( Tr -
Tr ) -
E ni .
VI -
f- ni .
V,
'
p
.
Tz = 300°C =
573k zin =
f- Vs -
Az
V, 155 MIS
0,8 -105
=
p,
A
'
Pr =
0.8077 Kg/m
}
0,0090M
= =
¥0
=
Vz = 240 MIS
K) DI 0,8077
(v =
700 Jllkg = 155 0,0090=1,1267 Kg Is
.
- .
R = 350 ) / ( kg -
r ) (p = R -
(~ = 350 +700 = 1050
I. Iri
'
DER =
vi. ui -
-
k =
E- 111267.2402 -
} 1,1267-
. 1552 =
18914 , 47625
✓ = -
1,1267 -
1050 .
(573 -
283 ) -
18914,47625
=
362007)
-
, OQ 8. 3. 1. a .
[ = 325 K Rs = (
p
-
(v
7th = 34% Cv =
71831kg -
K)
In
410kGBP
=
= 80MW f =
In =
1,4
op = 1005
JURG -
r)
PEP
1
4,28
Rs 287 Itr k)
=
= 0,34=1 -
OQ 8. 3. 1. b .
1
Pff 4,5165
t
1-2=280
=
k 0,35=1 -
7th = 35 % =
0,35
zin
350KGBP
=
""
= 70MW Tos =
( 4.5165 ) . . . .
°
280 = 430,77
(p = 1005
JURG r ) 7
Ja
-
70
R =
287911kg r) -
tho =
=
5 =
2,00 -108 ING
(v =
718911kg .rs Sho
✓ 14
Jllkg r) Ton -103 999k
=
= .
=
OQ 8. 7.1
TAS = 310 MIS DER = I. in .
ik
'
-
I. ni .kz
(j = 1050 MIS = I. 95 -
1050
'
-
I 95 - -
310
'
ni =
95kg Is Q =
(42000-103)-2,4 =
Ff
2,4kg Is t.95-1058-%95.rs
=
0,47g
42000
Rhg ga
=
Hoe = =
=
( 42000.103) -2,4
ij
ij
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