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Samenvatting rekenen in de chemie, hoofdstuk 2, nova havo 4 $4.32   Add to cart

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Samenvatting rekenen in de chemie, hoofdstuk 2, nova havo 4

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rekenen in de chemie, hoofdstuk 2, nova havo 4

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  • December 5, 2020
  • 1
  • 2020/2021
  • Summary
  • Secondary school
  • 4

1  review

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By: camilovanweerlee • 3 year ago

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Scheikunde H2
2.1 en 2.2
Mol: chemische hoeveelheid = aantal deeltjes

Getal van Avogadro (NA): 6,02  1023 = 1 mol

Liter xp Gram :M Mol  x NA Aantal
Volume ← :p Massa ← xM Hvl. stof ← : NA deeltjes (N)


p = dichtheid binas 8 t/m 12
M = molaire massa binas 98 en 99
NA = 6,02  1023

2.3
Massa stof X
Massapercentage =  100%
Totale massa

Volume stof X
Volumepercentage =  100%
Totale volume


Percentage =  100
Promillage ‰ =  1000
Ppm =  106
Ppb =  109

TGG-waarde: geeft aan hoeveel milligram van een stof er maximaal in 1 kubieke meter lucht
mag voorkomen zonder dat het risico’s voor de gezondheid oplevert.

Stappenplan:
1. Geef de kloppende reactievergelijking
2. Noteer de mol verhouding eronder
3. Reken de gegeven stof om naar mol
4. Reken m.b.v. de mol verhouding de gevraagde stof uit in mol
5. Reken de gevraagde eenheid uit

Overmaat: een reactie gaat zo lang door tot dat een van de beginstoffen op is, er blijft dan
een deel over van de andere beginstof en deze is dan in overmaat.

Stappenplan veranderd:
3. Reken BEIDE gegeven stoffen om naar mol
4. Vul in met de ideale mol verhouding, maak stappenplan af met de stof die niet in
overmaat is.

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