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CHEM 103 Final Exam (2 Versions, Latest-2022)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |Verified Q & A| CA$44.14   Add to cart
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CHEM 103 Final Exam (2 Versions, Latest-2022)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |Verified Q & A|

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  • Course
  • CHEM 103: General Chemistry I w/Lab
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  • Portage Learning

CHEM 103 Final Exam (2 Versions, Latest-2022)/ CHEM103 Final Exam / CHEM 103 General Chemistry Final Exam/ CHEM103 General Chemistry Final Exam: Portage Learning |Verified Q & A|

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  • November 2, 2022
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  • 2022/2023
  • Exam (elaborations)
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  • chem 103 final exam 2 versions
  • latest 2022 chem103 final exam chem 103 general chemistry final exam chem103 general chemistry final exam portage learning |verified q amp a|

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  • Portage Learning
  • CHEM 103: General Chemistry I w/Lab
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CHEM 103 Final Exam
Question 1
1. Convert 0.0000726 to exponential form and explain your answer.


2. Convert 5.82 x 103 to ordinary form and explain your answer.



Answer:
1. Convert 0.0000726 = smaller than 1 = negative exponent, move decimal 5
places = 7.26 x 10-5



2. Convert 5.82 x 103 = positive exponent = larger than 1, move decimal 3 places
= 5820


Question 2

Do the conversions shown below, showing all work:




1. 28oC = ? oK




2. 158oF = ? oC




3. 343oK = ? oF



Answer:

, 1. 28oC + 273 = 301 oK oC → oK (make larger) +273

2. 158oF - 32 ÷ 1.8 = 70 oC oF → oC (make smaller) -32 ÷1.8

3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF oK → oC → oF


Question 3

Show the calculation of the number of moles in the given amount of the following
substances. Report your answerto 3 significant figures.


1. 12.0 grams of Ca3(PO4)2

2. 15.0 grams of C9H8NO4Cl


Answer:

1. Moles = grams / molecular weight = 12..18 = 0.0387 mole



2. Moles = grams / molecular weight = 15..61 = 0.0653 mole




Question 4
Not yet graded / 10 pts


Click this link to access the Periodic Table.

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