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Solution Manual For Beginning Algebra 9th Edition by John Tobey, Jeffrey Slater, Jenny Crawford, Jamie Blair, All Chapters 1-10

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Beginning Algebra 9th Edition

Institution
Beginning Algebra 9th Edition

Solution Manual For Beginning Algebra 9th Edition by John Tobey, Jeffrey Slater, Jenny Crawford, Jamie Blair

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Uploaded on October 19, 2024
Number of pages 292
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Type Exam (elaborations)
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solution manual

Institution Beginning Algebra 9th Edition
Course Beginning Algebra 9th Edition

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INSTRUCTOR’S
R SOLUTIONS MANUAL

BEGINNING ALGEBRA
U
NINTH EDITION
E S
S
John Tobey
I
O
North Shore Community College
Danvers, Massachusetts
N
Jeffrey Slater
N
North Shore Community College
Danvers, Massachusetts
O
Jamie Blair
C
Orange Coast College
D
Costa Mesa, California
E
Jennifer Crawford
M
Normandale Community College
Bloomington, Minnesota

Boston Columbus Indianapolis New York San Francisco
Amsterdam Cape Town Dubai London Madrid Milan Munich Paris Montréal Toronto
Delhi Mexico City São Paulo Sydney Hong Kong Seoul Singapore Taipei Tokyo

, Contents
R
U
Chapter 0 1
E
Chapter 1 18
S
Chapter 2 37
S
Chapter 3 71
I
O
Chapter 4 92
N
Chapter 5 114
N
Chapter 6 135
O
Chapter 7 165
C
D
Chapter 8 198
E
Chapter 9 232
M
Chapter 10 256

Practice Final Examination 287

, Chapter 0
0.1 Exercises 8
25 1
26. = 3 25 = 8
13 3 24 3
2. : 17 is the denominator
17 1
R
3 17 11
4. 1: or 79 2
3 17 28. = 7 79 = 11
7 7
U
7
3 09
6. 3
4 7
E
2
S
20 5 × 4 5 15
8. = = 124 4 1
24 6 × 4 6 30. = 8 124 = 15 = 15
S
8 8 8 2
8 1× 8 1
10. = = 44
48 6 × 8 6
I
40
O
4
72 18 × 4
12. = =4
18 18 × 1
2 (4 × 5) + 2 20 + 2 22
N
32. 4 = = =
32 32 × 1 1 5 5 5 5
14. = =
64 32 × 2 2
N
1 (5 × 12) + 1 60 + 1 61
34. 5 = = =
33 11 × 3 3 12 12 12 12
= =
O
16.
55 11 × 5 5 5 (1 × 6) + 5 6 + 5 11
36. 1 = = =
6 6 6 6
63 9 × 7 7
C
18. = =
81 9 × 9 9 2 (6 × 3) + 2 18 + 2 20
38. 6 = = =
D
3 3 3 3 3
19 4
20. = 5 19 = 3
5 5 1 (10 × 9) + 1 90 + 1 91
15 = = =
E
40. 10
4 9 9 9 9
M
78
54
7
5 42. = 78 ÷ 6
22. = 7 54 = 7 6
7 49 7 13
5 6 78
6
6 18
41 5
24. = 6 41 = 6 18
6 36 6 0
5 78
= 13
6

Copyright © 2017 Pearson Education, Inc. 1

, Chapter 0: A Brief Review of Arithmetic Skills ISM: Beginning Algebra

5 ? 5 × 6 30 0.2 Exercises
44. = ⇒ =
9 54 9 × 6 54
2. You must change the fractions to equivalent
fractions with a common denominator.
5 ? 5 × 5 25
46. = ⇒ =
9 45 9 × 5 45 21 17
4. and
30 20
13 ? 13 × 3 39
= ⇒ = 30 = 2 ⋅ 3 ⋅ 5
R
48.
17 51 17 × 3 51 20 = 2 ⋅ 2 ⋅ 5
LCD = 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60
10 × 4 40
U
10 ?
50. = ⇒ =
15 60 15 × 4 60 5 1
6. and
18 24
E
7 ? 7 × 5 35 18 = 2 ⋅ 3 ⋅ 3
52. = ⇒ =
8 40 8 × 5 40 24 = 2 ⋅ 2 ⋅ 2 ⋅ 3
S
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 3 = 72
45 ? 45 × 2 90
54. = ⇒ =
S
50 100 50 × 2 100 5 7
8. and
16 48
20 5× 4 5 16 = 2 ⋅ 2 ⋅ 2 ⋅ 2
I
56. = =
424 106 × 4 106 48 = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3
O
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ 3 = 48
1400 70 × 20 70
58. = =
N
2420 121× 20 121 11 7
10. and
12 20
3 3 12 = 2 ⋅ 2 ⋅ 3
N
60. = is raisins
1+ 3 +1 5 20 = 2 ⋅ 2 ⋅ 5
LCD = 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60
O
1+ 3 4
62. = does not contain nuts 7 8
1+ 3 +1 5 12. and
30 45
C
6 6 3× 2 3 30 = 2 ⋅ 3 ⋅ 5
64. = = =
6 + 8 14 7 × 2 7 45 = 3 ⋅ 3 ⋅ 5
D
3 LCD = 2 ⋅ 3 ⋅ 3 ⋅ 5 = 90
of the students enrolled in 1994 were male.
7 1 3 9
E
14. , , and
Classroom Quiz 0.1 7 14 35
7=7
M
56 7 × 8 7 14 = 2 ⋅ 7
1. = = 35 = 5 ⋅ 7
88 11× 8 11
LCD = 2 ⋅ 5 ⋅ 7 = 70
11 (5 × 14) + 11 70 + 11 81
2. 5 ⇒ = = 3 5 11
14 14 14 14 16. , , and
8 12 42
109 1 8=2⋅2⋅2
3. =9 12 = 2 ⋅ 2 ⋅ 3
12 12
42 = 2 ⋅ 3 ⋅ 7
9
LCD = 2 ⋅ 2 ⋅ 2 ⋅ 3 ⋅ 7 = 168
12 109
108
1

2 Copyright © 2017 Pearson Education, Inc.

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Exam (elaborations)

Solution Manual For Beginning Algebra 9th Edition by John Tobey, Jeffrey Slater, Jenny Crawford, Jamie Blair, All Chapters 1-10

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