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, Oxford Cambridge and RSA
Friday 10 June 2022 – Afternoon
A Level Physics B (Advancing Physics)
H557/02 Scientific literacy in physics
Time allowed: 2 hours 15 minutes
You must have:
* 9 1 1 5 5 8 0 0 9 4 *
• a clean copy of the Advance Notice Article (inside
this document)
• the Data, Formulae and Relationships Booklet
You can use:
• a scientific or graphical calculator
• a ruler (cm/mm)
* H 5 5 7 0 2 *
Please write clearly in black ink. Do not write in the barcodes.
Centre number Candidate number
First name(s)
Last name
INSTRUCTIONS
• Use black ink. You can use an HB pencil, but only for graphs and diagrams.
• Write your answer to each question in the space provided. If you need extra space use
the lined pages at the end of this booklet. The question numbers must be clearly shown.
• Answer all the questions.
• Use the Insert to answer questions in Section C.
• Where appropriate, your answer should be supported with working. Marks might be
given for using a correct method, even if your answer is wrong.
INFORMATION
• The total mark for this paper is 100.
• The marks for each question are shown in brackets [ ].
• Quality of extended response will be assessed in questions marked with an asterisk (*).
• This document has 28 pages.
ADVICE
• Read each question carefully before you start your answer.
1 This question is about the experiment to measure the charge on an electron performed by
American physicists Robert Millikan and Harvey Fletcher in the early years of the twentieth
century.
Consider the forces on an oil drop falling at terminal velocity through air, as shown in Fig. 1.1.
D
W
Fig. 1.1
(a) Ignoring any upthrust forces, state why the drag force D must be equal and opposite to the
weight W of the drop when it is falling at terminal velocity.
(b) The drag force is given by the equation D = 6πηairrv where r is the radius of the oil drop and
v is the terminal velocity. The symbol ηair represents the viscosity of air; this is a measure of
the resistance that air has to the motion of objects in it.
Show that the terminal velocity of a drop of mass 1.8 × 10–15 kg is about 7 × 10–5 m s–1. The
buoyancy of air may be ignored.
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