Exam (elaborations)
AQA GCSE MAY 2023 TRIPLE SCIENCE PHYSICS FOUNDATION TIER 8463 PAPER 1 ACTUAL PAPER
AQA GCSE MAY 2023 TRIPLE SCIENCE PHYSICS FOUNDATION TIER 8463 PAPER 1 ACTUAL PAPER
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GCSE
PHYSICS
Foundation Tier Paper 1
F
Thursday 25 May 2023 Morning Time allowed: 1 hour 45 minutes
Materials For Examiner’s Use
For this paper you must have:
• a ruler Question Mark
• a scientific calculator 1
• the Physics Equations Sheet (enclosed). 2
3
Instructions
• Use black ink or black ball-point pen. Pencil should only be used for drawing. 4
• Fill in the boxes at the top of this page. 5
• Answer all questions in the spaces provided.
6
• Do not write outside the box around each page or on blank pages.
• Do all rough work in this book. Cross through any work you do not want to 7
be marked. 8
• If you need extra space for your answer(s), use the lined pages at the end of 9
this book. Write the question number against your answer(s).
• In all calculations, show clearly how you work out your answer. 10
TOTAL
Information
• The maximum mark for this paper is 100.
• The marks for questions are shown in brackets.
• You are expected to use a calculator where appropriate.
• You are reminded of the need for good English and clear presentation in
your answers.
*JUN2384631F01*
IB/H/Jun23/E6 8463/1F
, 2
Do not write
outside the
Answer all questions in the spaces provided. box
0 1 A student investigated how the current in a filament lamp varies with the potential
difference across the lamp.
Figure 1 shows the circuit used.
Figure 1
0 1 . 1 What is component P?
[1 mark]
0 1 . 2 Complete the sentences.
Choose answers from the box.
[2 marks]
charge current energy potential difference power
The ammeter in the circuit measures .
The voltmeter in the circuit measures .
*02*
IB/M/Jun23/8463/1F
, 3
Do not write
outside the
0 1 . 3 How will increasing the resistance of the variable resistor in Figure 1 affect each of box
the following quantities?
[3 marks]
Tick () one box in each row.
Stays the
Quantity Decreases Increases
same
Current in the circuit
Potential difference across the lamp
Total resistance of the circuit
0 1 . 4 A charge flow of 15 coulombs passed through the filament lamp in a time
of 60 seconds.
Calculate the current in the lamp.
Use the equation:
charge flow
current =
time
[2 marks]
Current = A
Question 1 continues on the next page
Turn over ►
*03*
IB/M/Jun23/8463/1F
, 4
Do not write
outside the
0 1 . 5 When the current in the filament lamp is 0.12 A, the potential difference across the box
lamp is 6.0 V.
Calculate the resistance of the filament lamp.
Use the equation:
potential difference
resistance =
current
[2 marks]
Resistance = Ω
*04*
IB/M/Jun23/8463/1F
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