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Straighterline General Chemistry 1 LAB CHEM101L Lab 4 Molar Mass COMPLETE Worksheet with LAB PHOTOS (New Version August 2024) Scored 100%£8.55
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Lab 4 Molar Mass CHEM101L
Straighterline Intro to Chemistry CHEM101L Lab 4 Molar Mass COMPLETE Worksheet
with LAB PHOTOS (New Version August 2024) Scored 100%
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Lab Report Format Expectations
Utilize college level grammar and professional formatting when completing this worksheet.
Report all equations in a proper mathematical format, with the correct signs and symbols.
Pre-Lab Questions
1. What are the units of molar mass?
Molar mass is given in grams per mole(g/mol)
2. Chemists utilize the “mole” because it allows us to obtain the mass of an element or compound,
and then know exactly how many atoms or molecules of that element or compound exist. Why
do you think knowing the number of atoms or molecules is important?
In chemistry, knowing how many atoms or molecules are present in a substance is essential.
Atomic numbers enable accurate measurement, comprehension of chemical reactions, property
prediction, and chemical bonding research. They also enable a fundamental understanding of
substances' behavior, characteristics, and reactions.
3. Note today’s date. Take that date and choose the atom in the periodic table corresponding to
that date. For example, if today is July 20th, you would choose Calcium, since it has an atomic
number of 20.
Now, take the element you have chosen and calculate how many atoms you would have if you
weighed out a 12 mg sample of that element. In your response, state today’s date, the element
you chose and your answer. The date must match the timestamp of your lab, and you must
show work for credit.
Date: May 3, 2024
Element: Cobalt (Co)
atomic number of element: 27 Calculation: 1023 1020
No. Of atoms: 1.226× 1020 =12 mg of Co
4. Suppose you have one mole of an element. How many atoms would you have? What is another
, Lab 4 Molar Mass CHEM101L
term for that number?
In chemistry, measurable quantities are connected to the atomic scale through the value of
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