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AQA A Level Physics May-June 2024 Question Paper 3BA (7408-3BA) £5.27   Add to cart

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AQA A Level Physics May-June 2024 Question Paper 3BA (7408-3BA)

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AQA A Level Physics May-June 2024 Question Paper 3BA (7408-3BA)

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  • November 14, 2024
  • 17
  • 2024/2025
  • Exam (elaborations)
  • Only questions
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A-level
PHYSICS
Paper 3
Section B Astrophysics

Monday 17 June 2024 Morning Time allowed: The total time for
Materials
both sections of this paper is
For this paper you must have: 2 hours. You are advised to
• a pencil and a ruler spend approximately
• a scientific calculator
• a Data and Formulae Booklet 50 minutes on this section.
• a protractor.
For Examiner’s Use
Instructions
• Use black ink or black ball-point pen. Question Mark
• Fill in the boxes at the top of this page. 1
• Answer all questions.
2
• You must answer the questions in the spaces provided. Do not write
outside the box around each page or on blank pages. 3
• If you need extra space for your answer(s), use the lined pages at the end of 4
this book. Write the question number against your answer(s).
TOTAL
• Do all rough work in this book. Cross through any work you do not want
to be marked.
• Show all your working.

Information
• The marks for questions are shown in brackets.
• The maximum mark for this paper is 35.
• You are expected to use a scientific calculator where appropriate.
• A Data and Formulae Booklet is provided as a loose insert.



*JUN2474083BA01*
IB/M/Jun24/E6 7408/3BA

, 2
Do not write
outside the
Section B box


Answer all questions in this section.


0 1
tyrionpapers.com
A student uses a refracting telescope in normal adjustment to make
observations of Jupiter.
The telescope has an angular magnification of 75

0 1 . 1 The eyepiece has a focal length of 22 mm.

Determine the distance between the eyepiece and the objective lens.
[2 marks]




distance = m


0 1 . 2 When viewed through the telescope, the image of Jupiter subtends an angle
of 1.7 × 10−2 rad.

Calculate, in km, the distance between the Earth and Jupiter.

mean radius of Jupiter = 7.0 × 104 km
[2 marks]




distance = km




*02*
IB/M/Jun24/7408/3BA

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