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Campbell Biology Ch. 6 - 10 Test Bank Questions With Verified Answers

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©BRIGHTSTARS EXAM SOLUTIONS 2024/2025 ALL RIGHTS RESERVED. 1 Campbell Biology Ch. 6 - 10 Test Bank Questions With Verified Answers Campbell's Biology, 9e (Reece et al.) Chapter 6 A Tour of the Cell This chapter introduces the topics of microscopy and cell fractionation, followed by a review...

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  • December 17, 2024
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©BRIGHTSTARS EXAM SOLUTIONS 2024/2025

ALL RIGHTS RESERVED.




Campbell Biology Ch. 6 - 10 Test Bank
Questions With Verified Answers



Campbell's Biology, 9e (Reece et al.)
Chapter 6 A Tour of the Cell


This chapter introduces the topics of microscopy and cell fractionation, followed by a review of
the cell and the major organelles and structures of eukaryotic cells. A challenge with this chapter
is to keep this data from simply being a list of parts. In addition to the structure and function of
individual organelles, questions probe student understanding of the cell as a dynamic,
interconnected system: the flow of membrane and proteins in the endomembrane system to the
plasma membrane; the flow of information from the nucleus to the cytoplasm; and the
connection between the cytoskeleton, the plasma membrane, and the extracellular matrix. An
evolutionary perspective goes beyond structural distinctions between prokaryotes and eukaryotes
to examine theories concerning the evolutionary origins of eukaryotes and key eukaryotic cell
structures.


Multipl - Answers✔Answer: C
Topic: Concept 6.1
Skill: Knowledge/Comprehension


2) The advantage of light microscopy over electron microscopy is that
A) light microscopy provides for higher magnification than electron microscopy.
B) light microscopy provides for higher resolving power than electron microscopy.


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, ©BRIGHTSTARS EXAM SOLUTIONS 2024/2025

ALL RIGHTS RESERVED.
C) light microscopy allows one to view dynamic processes in living cells.
D) light microscopy provides higher contrast than electron microscopy.

E) specimen preparation for light microcopy does not produce artifacts. - Answers✔Answer: C
Topic: Concept 6.1
Skill: Knowledge/Comprehension


3) A primary objective of cell fractionation is to
A) view the structure of cell membranes.
B) sort cells based on their size and weight.
C) determine the size of various organelles.
D) separate the major organelles so that their particular functions can be determined.

E) separate lipid-soluble from water-soluble molecules. - Answers✔Answer: D
Topic: Concept 6.1
Skill: Knowledge/Comprehension




4) In the fractionation of homogenized cells using centrifugation, the primary factor that
determines whether a specific cellular component ends up in the supernatant or the pellet is
A) the relative solubility of the component.
B) the size and weight of the component.
C) the percentage of carbohydrates in the component.
D) the presence or absence of nucleic acids in the component.

E) the presence or absence of lipids in the component. - Answers✔Answer: B
Topic: Concept 6.1
Skill: Knowledge/Comprehension
5) Which of the following correctly lists the order in which cellular components will be found in
the pellet when homogenized cells are treated with increasingly rapid spins in a centrifuge?
A) ribosomes, nucleus, mitochondria

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B) chloroplasts, ribosomes, vacuoles
C) nucleus, ribosomes, chloroplasts
D) vacuoles, ribosomes, nucleus

E) nucleus, mitochondria, ribosomes - Answers✔Answer: E
Topic: Concept 6.1
Skill: Application/Analysis


6) Green fluorescent protein (GFP) can be used to fluorescently label a specific protein in cells
by genetically engineering cells to synthesize the target protein fused to GFP. What is the
advantage of using GFP fusions to visualize specific proteins, instead of staining cells with
fluorescently labeled probes that bind to the target protein?
A) GFP fusions enable one to track changes in the location of the protein in living cells; staining
usually requires preserved cells.
B) GFP fusions enable higher resolution than staining with fluorescent probes.
C) GFP permits the position of the protein in the cell more precisely than fluorescent probes.
D) GFP permits visualization of protein-protein interactions; fluorescent probes do not.
E) GFP fusions are not subject to artifacts; fluorescent probes may introduce background
artifacts. - Answers✔Answer: A
Topic: Concept 6.1
Skill: Application/Analysis


7) What is the reason that a modern electron microscope (TEM) can resolve biological images to
the subnanometer level, as opposed to tens of nanometers achievable for the best super-
resolution light microscope?
A) The focal length of the electron microscope is significantly longer.
B) Contrast is enhanced by staining with atoms of heavy metal.
C) Electron beams have much shorter wavelengths than visible light.
D) The electron microscope has a much greater ratio of image size to real size.

E) The electron microscope cannot image whole cells at one time. - Answers✔Answer: C


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ALL RIGHTS RESERVED.
Topic: Concept 6.1
Skill: Application/Analysis


8) What technique would be most appropriate to use to observe the movements of condensed
chromosomes during cell division?
A) light microscopy
B) scanning electron microscopy
C) transmission electron microscopy
D) confocal fluorescence microscopy

E) super-resolution fluorescence microscopy - Answers✔Answer: A
Topic: Concept 6.1
Skill: Synthesis/Evaluation


9) All of the following are part of a prokaryotic cell except
A) DNA.
B) a cell wall.
C) a plasma membrane.
D) ribosomes.

E) an endoplasmic reticulum. - Answers✔Answer: E
Topic: Concept 6.2
Skill: Knowledge/Comprehension


10) The volume enclosed by the plasma membrane of plant cells is often much larger than the
corresponding volume in animal cells. The most reasonable explanation for this observation is
that
A) plant cells are capable of having a much higher surface-to-volume ratio than animal cells.
B) plant cells have a much more highly convoluted (folded) plasma membrane than animal cells.
C) plant cells contain a large vacuole that reduces the volume of the cytoplasm.

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