100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
MATH 225N WEEK 7 HYPOTHESIS TESTING Q & A / MATH225N WEEK 7 HYPOTHESIS TESTING Q & A (LATEST) : CHAMBERLAIN COLLEGE OF NURSING $15.49   Add to cart

Exam (elaborations)

MATH 225N WEEK 7 HYPOTHESIS TESTING Q & A / MATH225N WEEK 7 HYPOTHESIS TESTING Q & A (LATEST) : CHAMBERLAIN COLLEGE OF NURSING

 5 views  0 purchase
  • Course
  • Institution

MATH 225N WEEK 7 HYPOTHESIS TESTING Q & A / MATH225N WEEK 7 HYPOTHESIS TESTING Q & A (LATEST) : CHAMBERLAIN COLLEGE OF NURSING MATH 225N WEEK 7 HYPOTHESIS TESTING Q & A Steve listens to his favorite streaming music service when he works out. He wonders whether the service algorithm does a good job ...

[Show more]

Preview 4 out of 32  pages

  • August 29, 2021
  • 32
  • 2021/2022
  • Exam (elaborations)
  • Questions & answers
avatar-seller
MATH 225N: Week 7 Hypothesis Testing Q &
A, Chamberlain college of nursing


1. Steve listens to his favorite streaming music service when he works out. He wonders whether the
service algorithm does a good job of finding random songs that he will like more often than not. To
test this, he listens to 50 songs chosen by the service at random and finds that he likes 32 of them.
Use Excel to test whether Steve will like a randomly selected song more than not and then draw a conclusion in the
context of a problem. Use α = 0.05. Type equation here .
Ho: p = ≤ 0.5 (50%) p = 0.5
Ha: p = > 0.5 (strictly ¿>≠ )
P-value = 0.02 which is < α =0.05 we reject Ho and support the Ha
Hypothesis Test for p population
proportion

(decimal
Level of Significance 0.05 )
(decimal
Proportion under H0 0.5000 )
n 50
Number of
Successes 32




0.64000
Sample Proportion 0
0.50000
StDev 0
0.07071
SE 1
1.97989
Test Statistic (z) 9
0.02385
One-Sided p-value 2
0.04770
Two-Sided p-value 4


Right-Tailed (>) 1.644854
Left-Tailed (<) -1.644854
Two-Tailed (≠) ± 1.959964

,Answer: Reject the null hypothesis. There is sufficient evidence to prove that Steve will like a random selected song
more often than not.
2. A magazine regularly tested products and gave the reviews to its customers. In one of its reviews, it
tested 2 types of batteries and claimed that the batteries from company A outperformed batteries
from company B in 108 of the tests. There were 200 tests. Company B decided to sue the magazine,
claiming that the results were not significantly different from 50% and that the magazine was
slandering its good name.
Use Excel to test whether the true proportion of times that Company A’s batteries outperformed Company B’s batteries
is different from 0.5. Identify the p=value rounding it to 3 decimal places.
Ho: p = 0.5 Ha ≠ 0.5 (two tailed test) n = 200 (α is not given so leave it 0.05)
Hypothesis Test for p population
proportion

Level of Significance 0.05
Proportion under H0 0.5000
n 200
Number of Successes 108




Sample Proportion 0.540000
StDev 0.500000
SE 0.035355
Test Statistic (z) 1.131371
One-Sided p-value 0.129238
Two-Sided p-value 0.258476

Right-Tailed (>) 1.644854
-
Left-Tailed (<) 1.644854
Two-Tailed (≠) ± 1.959964
Answer: 0.258 (because it is a two tailed test). We are not rejecting the null hypothesis and we do not have evidence to
support the alternative hypothesis.
3. A candidate in an election lost by 5.8% of the vote. The candidate sued the state and said that more
than 5.8% of the ballots were defective and not counted by the voting machine, so a full recount
would need to be done. His opponent wanted to ask for the case to be dismissed, so she had a
government official from the state randomly select 500 ballots and count how many were defective.
The official found 21 defective ballots.
Use Excel to test if the candidates claim is true and that < 5.8% of the ballots were defective. Identify the p=value
rounding to 3 decimal places.
Ho: p = ≥ 0.058 Ha ¿ 0.058 (one tailed test) n = 500 (α is not given so leave it 0.05)
Hypothesis Test for p population
proportion

Level of Significance 0.05 (decimal)
Proportion under H0 0.0580 (decimal)
n 500

,Number of Successes 21




Sample Proportion 0.042000
StDev 0.233743
SE 0.010453
-
Test Statistic (z) 1.530613
One-Sided p-value 0.063008
Two-Sided p-value 0.126016


Right-Tailed (>) 1.644854
-
Left-Tailed (<) 1.644854

Two-Tailed (≠) ± 1.959964
Answer: 0.063


4. A researcher claims that the incidence of a certain type of cancer is < 5%. To test this claim, a
random sample of 4000 people are checked and 170 are found to have the cancer.
The following is the set up for the hypothesis:
Ho = 0.05
Ha = < 0.05
In the example the p-value was determined to be 0.015.
Come to a conclusion and interpret the results of this hypothesis test for a proportion (use a significance level of 5%)
Answer: The decision is to reject the null hypothesis. The conclusion is that there is enough evidence to support the
claim.


5. A researcher is investigating a government claim that the unemployment rate is < 5%. TO test this
claim, a random sample of 1500 people is taken and it is determined that 61 people were
unemployed.
Ho: p = 0.05 Ha: p < 0.05
Find the p-value for this hypothesis test for a proportion & round to 3 decimal places.
Hypothesis Test for p
population proportion

Level of Significance 0.05
Proportion under H0 0.0500
n 1500
Number of
Successes 61

, 0.04066
Sample Proportion 7
0.21794
StDev 5
0.00562
SE 7
-
1.65857
Test Statistic (z) 7
0.04845
One-Sided p-value 7
0.09691
Two-Sided p-value 4



Answer: 0.048


6. An economist claims that the proportion of people that plan to purchase a fully electric vehicle as
their next car is greater than 65%.
To test this claim, a random sample of 750 people were asked if they planned to purchase a fully electric vehicle as their
next car. Of this 750, 513 indicated that they plan to purchase an electric vehicle.
Ho: p = 0.65 Ha; p = >0.65
Find the p-value for this hypothesis test for a proportion & round to 3 decimal places.
Hypothesis Test for p
population proportion

Level of Significance 0.05
Proportion under H0 0.6500
n 750
Number of
Successes 513




0.68400
Sample Proportion 0
0.47697
StDev 0
0.01741
SE 6
1.95217
Test Statistic (z) 5
0.02558
One-Sided p-value 8
0.05117
Two-Sided p-value 6


Answer: 0.026

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller HIGHSCORE. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $15.49. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

75632 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$15.49
  • (0)
  Add to cart