Exam (elaborations)

Exam (elaborations) TEST BANK FOR Computer Architecture A Quantitative Approach 4th Edition By John L. Hennessy & David Patterson (Solution manual)

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Harvard University

Book
Computer Architecture

Exam (elaborations) TEST BANK FOR Computer Architecture A Quantitative Approach 4th Edition By John L. Hennessy & David Patterson (Solution manual) L.1 Chapter 1 Solutions L-2 L.2 Chapter 2 Solutions L-7 L.3 Chapter 3 Solutions L-20 L.4 Chapter 4 Solutions L-30 L.5 Chapter 5 Solutions L-...

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Uploaded on November 7, 2021
Number of pages 66
Written in 2021/2022
Type Exam (elaborations)
Contains Questions & answers

test bank for computer architecture a quantitative approach 4th edition by john l hennessy amp david patterson
test bank
computer architecture a quantitative approach
john l hennessy amp david p

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L.1 Chapter 1 Solutions L-2 L.2 Chapter 2 Solutions L-7 L.3 Chapter 3 Solutions L-20 L.4 Chapter 4 Solutions L-30 L.5 Chapter 5 Solutions L-46 L.6 Chapter 6 Solutions L-52 L Solutions to Case Study Exercises L-2 I Appendix L Solutions to Case Study Exercises Case Study 1: Chip Fabrication Cost 1.1 a.
b.
c. The Sun Niagara is substantially larger, since it places 8 cores on a chip rather
than 1. 1.2 a.
b.
c. $9.38 × .4 = $3.75 d. Selling price = ($9.38 + $3.75) × 2 = $26.26
Proﬁt = $26.26 – $4.72 = $21.54 e. Rate of sale = 3 × 500,000 = 1,500,000/month
Proﬁt = 1,500,000 × $21.54 = $32,310,000
$1,000,000,000/$32,310,000 = 31 months 1.3 a.
b. Prob of one defect = 0.29 × 0.71 7 × 8 = 0.21
Prob of two defects = 0.29 2 × 0.71 6 × 28 = 0.30
Prob of one or two = 0.21 × 0.30 = 0.51 c. 0.71 8 = .06 (now we see why this method is inaccurate!)L.1 Chapter 1 Solutions
Yield 10.7 × 1.99
4.0------------------------ - +4–
0.28 ==
Yield 10.75 × 3.80
4.0--------------------------- - +4–
0.12 ==
Yield 10.30 × 3.89
4.0--------------------------- - +4–
0.36 ==
Dies per waferπ × 30 2⁄()2
3.89------------------------------=π × 30
sqrt 2 × 3.89 ()----------------------------------– 182 33.8 148 = – =
Cost per die$500
148 × 0.36-------------------------- $9.38 ==
Yield 1.7 × 1.86
4.0--------------------- - +4–
0.32 ==
Dies per waferπ × 30 2⁄()2
1.86------------------------------=π × 30
sqrt 2 × 1.86 ()----------------------------------– 380 48.9 331 = – =
Cost per die$500
331 × .32----------------------- $4.72 ==
Yield 1.75 × 3.80 8 ⁄
4.0------------------------------- - +4–
0.71 ==
Prob of error 1 0.71 – 0.29==

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