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BIO 171 Module 4 Exam Questions and Answers- Portage Learning 2022 $15.49   Add to cart

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BIO 171 Module 4 Exam Questions and Answers- Portage Learning 2022

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  • February 11, 2022
  • 10
  • 2022/2023
  • Exam (elaborations)
  • Questions & answers

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By: EduMerit • 2 year ago

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M4: Module 4 Exam - Requires Respondus
LockDown Browser + Webcam
Attempt Time Score

LATEST Attempt 1 28 minutes 98 out of 100
Score for this quiz: 98 out of 100
Submitted Aug 6 at 10:30am
This attempt took 28 minutes.

Question 1
pts
True or False: Growth media is best suited for distinguishing between two similar
species of bacteria.


True

Correct!

False

Growth media is designed to simply support (and not restrict) microbial growth.


Question 2
pts
A researcher is asked to determine which of two vials contains E coli and which
contains salmonella. Knowing both are Gram-negative while only one of them is capable
of fermenting lactose, which type of media would be best suited?


Selective and Differential media



Selective media



Growth media

, Correct!

Differential media

Differential media distinguishes between two, often related, microbes.


Question 3
pts
What are the requirements of a fastidious microbe?
Your Answer:
A fastidious microbe is organism with complex growth requirements. If these growth
requirements are not met, the organism will not grow. An enriched media must be to
provide the correct nutrients to the organism to allow for growth.
A fastidious microbe is an organism with complex growth requirements such that
if absent it will not grow. Enriched medias thus contain these specific and
essential nutrients required for the growth of a particular subset of
microorganisms.


Question 4
pts
True or False: LB agar is classified as a non-selective, non-differential media.
Correct Answer

True

You Answered

False



Question 5
pts
What is agar used for in microbiology?
Your Answer:
Agar is used to create a solid, smooth surface on which microbes can grow.
Agar is used to create a solid, smooth surface on which microbes can grow.

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