CHEM 108 PRACTICE FINAL EXAM ANSWERS- PORTAGE LEARNING
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Course
CHEM 108
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Portage Learning
CHEM 108 PRACTICE FINAL EXAM ANSWERS- PORTAGE LEARNING///CHEM 108 PRACTICE FINAL EXAM ANSWERS- PORTAGE LEARNING///CHEM 108 PRACTICE FINAL EXAM ANSWERS- PORTAGE LEARNING
chem 108 practice final exam answers portage learning
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CHEM 108
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PRACTICE EXAM
Using the following information, complete the two conversions shown below, showing all work:
1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts
1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints
kilo (= 1000) milli (= 1/1000) centi (= 1/100) deci (= 1/10)
25.6 mg = ? grams
25.6 mg x 1 g / 1000 mg = 0.0256 grams
1.5 gal = ? qts
1.5 gal x 4 qts / 1 gal = 6.0 qts
Write the formula for each of the following 3 chemical compounds explaining the answer with
appropriate charges and/or prefixes and/or suffixes.
Titanium (IV) hydroxide
Titanium (IV) hydroxide - Ti+4, OH-1 = Ti(OH)4
Hydrobromic acid
Hydrobromic acid - hydro = binary acid of H + Br-1 = HBr
Dichlorine heptoxide
Dichlorine heptoxide - ide = binary, two Cl, 7 O = Cl2O7
Show the calculation of the empirical formula for each compound whose elemental composition is
shown below.
27.60% Mn, 24.17% S, 48.23% O
27.60% Mn / 54.94 = 0..5024 = 1 x 2 = 2
24.17% S / 32.07 = 0..5024 = 1.5 x 2 = 3
, 48.23% O / 16.00 = 3..5024 = 6 x 2 = 12 → Mn2S3O12
Balance the equation and show the calculation of the number of moles and grams of CH4 formed
from 17.3 grams of H2O. Show your answers to 3 significant figures.
Al4C3 + H2O → Al(OH)3 + CH4
Al4C3 + 12 H2O → 4 Al(OH)3 + 3 CH4
17.3 g / (2 x 1.008 + 1 x 16.00) = 17..016 = 0.9603 mole x 3/12 = 0.240 mole CH4
0.240 mole CH4 x (12.01 + 4 x 1.008) = 3.85 g CH4
Show the calculation of the new pressure of a gas sample which has an
original volume of 540 ml when collected at 1.10 atm and 27 oC when the
volume becomes 1.20 liters at 45oC.
Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the K19 atom and identify which are
valence (outer shell) electrons and determine how many valence electrons there are.
Determine the shape and explain your answer for HCN.
The C atom in HCN has 2 groups of electrons around it in its Lewis structure, therefore, its electron
geometry would be linear and since there are 2 atoms around the central C atom, the shape would
be linear.
Explain whether N2 is Polar, Ionic or Non-polar.
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