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Ejercicio propuesto. Estequiometría. Química General $4.85
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Ejercicio propuesto. Estequiometría. Química General
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  • Course
  • Química General
  • Institution
  • Universidad Politécnica Salesiana

Se realizó un planteamiento de un ejercicio donde se pretende encontrar el rendimiento de la solución, además del reactivo limitante y el reactivo en exceso, todo ello a través de la estequiometría.

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  • February 23, 2022
  • 1
  • 2021/2022
  • Other
  • Unknown

Subjects

  • estequiometría
  • soluciones
  • reactivos
  • reactivo en exceso
  • reactivo limitante
  • rendimiento

Written for

  • Universidad Politécnica Salesiana
  • Biotecnología
  • Química General
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TALLER No 6
2 C4H10 + 13 O2 8 CO2 + 10 H2O

Si se combinan 10 gramos de Oxígeno con 5 gramos de butano, precisar la
cantidad de agua que se produce, establecer cuál es el reactivo limitante y el
reactivo en exceso.
Indicar el rendimiento cuando en la reacción se han obtenido 3.3 gramos de
H2O.



VALOR CALCULADO – VALOR OBTENIDO
RENDIMIENTO = ------------------------------------------------------- x 100

VALOR CALCULADO

1 mol de O2 10 moles H2O 18 g H2O
10 g O2 x ---------------------- x ------------------------- x --------------------
32 g de O2 13 moles O2 1 mol H2O

= 4,32 g H2O Reactivo limitante

1 mol C4H10 10 moles H2O 18 g H2O
5 g C4H10 x ------------------- x -------------------------- x ----------------
58 g C4H10 2 moles de C4H10 1 mol H2O

= 7,75 g H2O

Se produce 4,32 g H2O. El reactivo limitante es Oxígeno y el
reactivo en exceso el Butano.
4,32 g – 3,3 g
RENDIMIENTO = ----------------------------------x 100 = 23,61
4,32 g

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