Biochemistry Readiness Check 1B
The 2nd OA Readiness Check is designed to give you additional practice with new assessment- style questions to help prepare for success on the OA. Thus, please try to mimic exam-like conditions by taking the test in one <2 hr sitting without any study aids apart ...
Biochemistry Readiness Check 1B
The 2nd OA Readiness Check is designed to give you additional practice with new
assessment- style questions to help prepare for success on the OA. Thus, please try
to mimic exam-like conditions by taking the test in one <2 hr sitting without any
study aids apart from your whiteboard/scrap paper.
Note: Responses cannot be edited. You will be able to see the results and
feedback after submitting the test. A score of 70% is required for OA approval. If
you score below 70%, please speak with a Course Instructor via appointment to
discuss next steps prior to retaking this test.
Points: 53/67
1
What is the complementary sequence to 3’ CAG TAA CAA
5’? * (0/1 Point)
5' TTG TTA CTG 3
The correct answer is 3' TTG TTA CTG 5'. Remember complementary means
“Matching or Pairing” You have to remember to pay attention to your numbers as
well as your letters (A-T, G-C, 5'-3'). The correct answer is 3’ CAG TAA CAA 5’ (original
sequence) 5’ GTC ATT GTT 3’ (complementary sequence) But we asked for it in the 3’
direction, so mirror answer to give correct answer: 3’ TTG TTA CTG 5’ If you chose 5'
GTC ATT GTT 3', this sequence is just the mirror of the original
,12/12/2020 Biochemistry Readiness Check 1B
sequence provided, and is not its complementary sequence. No "pairing" was
done to get this sequence.
3’ GTC ATT GTT 5’
3’ GTT ATT GTC 5’
3' TTG TTA CTG 5
2
Which amino acid sequence would result from this Coding DNA
strand? 3’ TAC GTT AAC 5’? *
(0/1 Point)
Gln Leu His
,12/12/2020 Biochemistry Readiness Check 1B
Met Gln Leu
The correct answer is Gln Leu His. We are starting at the coding strand, and have to
remember the relationship between coding DNA and mRNA. These two strands are
non-complementary and parallel. So we copy the coding strand , change T ---> U, and
then write the mRNA sequence: 3’ TAC GTT AAC 5’ coding 3’ UAC GUU AAC 5’ mRNA
Mirror by changing orientation: 5’ CAA UUG CAU 3’ Read chart Gln Leu His (chart is in
direction of 5' ---> 3') If you chose Met Gln Leu, this answer is incorrect because this is
the amino acid sequence that results from the mRNA 5' AUG CAA UUG 3' which would
have been complementary to the given coding strand. Coding DNA is non-
complementary and parallel to mRNA.
Ile Asp
Val Gln
Ile Met
3
Which amino acid sequence would be made from this template DNA strand?
5’
AGT TAT AAC 3’? *
(0/1 Point)
, 12/12/2020 Biochemistry Readiness Check 1B
Met Leu Thr
Val Ile Thr
Ser Tyr Asn
The correct answer is Val Ile Thr because 5’ AGT TAT AAC 3’ template is complementary
and
antiparallel so 3’ UCA AUA UUG 5’ but it is in the wrong orientation, so mirror 5’ GUU
AUA ACU 3’ and read the chart Val Ile Thr
Gln Tyr
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