Chem 104 Module 1 Exam answers Portage learning 2022
Score for this quiz: 0 out of 0 * Submitted Jun 17 at 2:59pm This attempt took 6 minutes.
In the reaction of 0.200 M gaseous N2O5 to yield NO2 gas and O2 gas as shown below:
2 N2O5 (g) → 4 NO2 (g) + O2 (g)
the following dat...
2022 2022
Question 1 Not yet graded / 0 pts2
PORTAGE LEARNING CHEM 104
2022
Module 1: Problem Set
Due No due datePoints 0Questions 18Time Limit None
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Score for this quiz: 0 out of 0 * Submitted Jun 17 at 2:59pm This attempt took 6 minutes.
In the reaction of 0.200 M gaseous N2O5 to yield NO2 gas and O2 gas as shown below:
2 N2O5 (g) → 4 NO2 (g) +O2 (g)
the following data table is obtained:
Time (sec)[N2O5][O2]
1 2022 20222
00.200 M0
3000.180 M0.010 M
600 0.019 M
2 2022 20222
9000.146 M0.027 M
12000.132 M0.034 M
18000.110 M0.045 M
24000.096 M0.052 M
30000.092 M0.054 M
(a)Use the [O2] data from the table to calculate the average rate over the measured time interval from 0 to 3000 secs.
(b)Use the [O2] data from the table to calculate the instantaneous rate early in the reaction (0 secs to 300 sec).
(c)Use the [O2] data from the table to calculate the instantaneous rate late in the reaction (2400 secs to 3000 secs).
(d)Explain the relative values of the average rate, early instantaneous rate and late instantaneous rate.
Your Answer:
.
3 2022 20222
(a)The average rate over the measured time interval from 0 to 3000 secs is:
rate = ∆[O2] / ∆t = (0.054 - 0) / 3000 - 0 = 1.80 x 10-5 mol/L•s
(b)The instantaneous rate early in the reaction from 0 to 300 secs is:
rate = ∆[O2] / ∆t = (0.010 - 0) / 300 - 0 = 3.33 x 10-5 mol/L•s
(c)The instantaneous rate late in the reaction from 2400
to 3000 secs is:
rate = ∆[O2] / ∆t = (0.054 - 0.052) / 3000 - 2400 = 3.33 x 10-6
mol/L•s
(d)It can be seen that the early instantaneous rate is the largest since the concentrations of reactants is highest during the earliest stages of the reaction and the late instantaneous rate is smallest since the concentrations of reactants is lowest during the late stages of the reaction.
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