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BIOD 151 FINAL EXAM A&P 1. Portage Learning

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• BIOD 151 FINAL EXAM A&P 1. Portage Learning List two organs contained in the abdominal cavity. Your Answer: small intestine and large intestine The abdominal cavity contains the stomach, intestines, spleen and liver True or False? a. The purpose of cellular respiration is to pr...

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  • December 17, 2022
  • 17
  • 2022/2023
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BIOD 151 FINAL EXAM A&P 1. Portage Learning
Question 1
pts
List two organs contained in the abdominal cavity.
Your Answer:
small intestine and large intestine
The abdominal cavity contains the stomach, intestines, spleen and liver


Question 2
pts
True or False?


a. The purpose of cellular respiration is to produce ADP. (T or F)

b. Peripheral proteins are found on the outer surface of a cell membrane. (T or
F)

c. Exocytosis is the process that occurs to bring biomacromolecules inside
the cell. (T or F)

d. Receptor-mediated endocytosis uses a signaling molecule from another
cell, binding to the cell membrane to bring about changes within the cell
proteins. (T or F)

e. Endocytosis is a passive process. It does not require cellular energy
expenditure.(T or F)
Your Answer:
a. False
b. True
c. False
d. True
e. False
a. False- (ATP is produced, not ADP)
b. True
c. False- (This process is called endocytosis)
d. True

,e. False- (Endocytosis is an active process and requires cellular energy)

, Question 3
pts
Note: Essay answers must clearly be in your own words.


In your own words, discuss Tay-Sachs disease. What organelle within the cell
is impacted? What are the symptoms of the disease and why do they occur?
Your Answer:
Tay-Sachs disease impacts the lysosome of the cell. This leads to a toxic
buildup of toxins in the brain. This can lead to disability and death.
(1) Lysosomes
(2) buildup of toxic lipids inside the cell (biomacromolecules)
(3) disability and death
In the genetic disease known as Tay-Sachs, one of the normally present
digestive enzymes inside lysosomes is lacking. Thus, a toxic lipid in the brain
cells cannot be broken down. The resulting buildup of lipids in these cells can
cause intellectual disability and death.


Question 4
pts
Note: Essay answers must clearly be in your own words.


You are observing two cells under the microscope. They are the same type
of eukaryotic cell but one appears much larger. Based on appearance alone,
which one would you expect to be carrying out respiration at a more active
rate, the larger or smaller cell? Explain why.
Your Answer:
The smaller cell would carry out respiration at a more active rate. This is
because of the increased surface area compared to larger cells.
The smaller cell. Cells need to remain relatively small because as a cell expands
the amount of surface area relative to the volume of the cell decreases. The
smaller cell is more active because relative to its volume, its surface area is
larger than a bigger cell. With a larger surface area (relative to its volume) this
allows the metabolic processes to occur faster.


Question 5
pts
Note: Essay answers must clearly be in your own words.

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