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Gases Ideales (Sistemas Cerrados y Abiertos)
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Incluye la teoría necesaria para la resolución de problemas de gases ideales en sistemas cerrados y abiertos.
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ECUACI ONES IMPORTANT ESGAS PERFECTO :
R"
Ecuaciéntérmica de estado de gas ideal : PV=mRgT I Rg =
M
du = wolf =
Uz -
Us = Cv /Tz -
Ti )
01h =
Cpdt →
hz hi- =
Cp / Tz T, )
-
ds = Cp 01T Rg
T
-
%P '
sa s,-
=
Cpln T2
T,
-
Rg In ¥ = Cv In
?
-1
Rg In V2
K
Cp -
Cv = Rg
D= Cp
Cv
SISTEMAS INCOMPRESIBLES :
Ecuaciéntérmica : Kate → Pete
U2 U1=c
-
(1-2-1-1)
hz h , / Tz T, ) -1 Pz Pi
-
-
= c -
p
52 5 ,
- = c In T2
T,
PRIMER PRINCIP 10 DE LA TERM ODIN A'MICA :
Balance energético : E= Next , s + Qs
t.s-SE-r-wdsdlt-cttpl-swext.s.SE?ipdV-XrdXrEcuacioin
Ecuaciin de la energia meianica: dl Ect Ep) = SHE ✗
?
de la energia interna: dU=SQst8E pdvtxrdxr
Relacién Calor y trabajo disipadoporfriccién : SQ , -180,2 =
SET
Relacién trabajo y trabajo disipadoporfricciin : 8W 1,2 -18W2,1 = -
SEO
SEGUNDO PRINCIPI 0 DE LA TERM ODIN A' MICA :
motor térmico : 12 = W / W=Q Qz ) Q2
Rendimiento de un ,
- =
12=1 -
Qi QI
Coeficiente de operaci ones COPMF = Q2 Q2
frigorifica
'
de una ma
qui na : =
W Q, Q2-
Coeficiente de operaci ones de una Bomba de Calor : cop Bc =
Q' =
Q
"
COPBC = COPMF -11
W Q -
Q2
.
, Rendimiento de un motor de Carnot: 1C:1.T2
TI
Coeficient T2
desperaciones denna maquina frigorifica de Carnot: COPME
T1 -T2
-
Coeficient bomba decolor de Carnot: COPBC: T1 COPBC=COPMF + 1
desperaciones deuna
Tt T2
Rendimiento deven motor endorreversible: Kendrex= 1.THTB
TiTA
Teorema de la designaldad de Clausius:
-80
Formulacion del segundo principio:
seosto re
rreversibilidad interna: Tamb. Oi
A
↑
rreversibilidad del process: Tamb.Up
Acuacion be Gibbs: DU: TdS-pdV
5 Gi +Up No habra produccion de entropia cuando el process sea reversible.
Trig
35: Sai 8 Up -Compresion/expansion adiabatica de un
gas. Chando usar el
Tig
segundo principio
dS: Oi Up -
Transferencia de calor infinitesimal chands el tiempo del processes infinite.
at Fig
Usavemos e)segnolo principio cuando el sistema sea reversible.
Ecuacion de Gibbs: dU= TdS-polv
ds=<pdT-RgdDs=<pInteRgIn
d
=<d+ +Rg dr s
=CxInt+RgIn we
- V2
V,
·so -S4.54 +60c =0 (Fronteral
SE TT T
↓
Sistema + SKc=881. I
#
· SO Tit
Sistema: dS: S8
TFT
+5Up dS:Sy +Sun
so dS =50 +5Up
FT
T ds:
So +5O:84c TFT
⑤Di
=>
Irreversibilidad:FTamb Tp
sien los problemas has preguntan por Ia irreversibilidad has que calcular la producien be entropia (Up).
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