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MIP1502 Assignment 3 2023 (787060) - DUE 4 July 2023 $3.00   Add to cart

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MIP1502 Assignment 3 2023 (787060) - DUE 4 July 2023

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  • June 21, 2023
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MIP1502
Assignment 3
2023 (787060) -
DUE 4 July
2023
QUESTIONS AND ANSWERS

lenovo
[COMPANY NAME]

, MIP1502 Assignment 3 2023 (787060) - DUE 4 July 2023

Question 1
1.1 If Lize would continue counting 3; 8; 13; ….
1.1.1 What is the 100th number that she will count? Show Lize how to
calculate the 100th number instead of actually counting all the way up
to the 100th number. (6)
If Lize continues counting with a pattern of adding 5 to each previous number (3,
8, 13, ...), we can calculate the 100th number without actually counting all the way
up to it.


To find the 100th number, we can use the formula for an arithmetic sequence:


nth term = first term + (n - 1) * common difference


In this case, the first term is 3, and the common difference is 5.


So, the 100th number (n = 100) can be calculated as follows:


100th number = 3 + (100 - 1) * 5
= 3 + 99 * 5
= 3 + 495
= 498


Therefore, the 100th number Lize will count is 498.
1.1.2 Will Lize count 996? Explain your reasoning (4)

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