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Solutions for University Physics for the Life Sciences, 1st edition by Knight $29.49   Add to cart

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Solutions for University Physics for the Life Sciences, 1st edition by Knight

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  • University Physics
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  • University Physics

Complete Solutions Manual for University Physics for the Life Sciences, 1st edition 1e by Randall D Knight, Brian Jones, Stuart Field. ISBN-13: 4722 Complete Chapters Solutions Manual are included Physics for the Life Sciences Describing Motion Motion Along a Line Force and Motion Interac...

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  • July 28, 2023
  • 1131
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  • Exam (elaborations)
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  • University Physics
  • University Physics

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Complete Solutions Manual included

University Physics for the Life Sciences, 1st
edition Knight

ALL CHAPTERS
INCLUDED

, PHYSICS FOR THE LIFE SCIENCES
!"
QUESTIONS
Q1.1 REASON: We know from the reading that diffusion distances scale with the square root of time. Specifically,
Equation 1.3 tells us xrms = 2 Dt . So, if the time were quadrupled, we would expect the diffusion distance to

double from d to 2d .

ASSESS: This is not specific to one dimension. Equation 1.5 for three dimensions reads rrms = 6 Dt . It has a

different numerical constant, but the dependence on time is the same.
1
Q1.2 REASON: The diffusion constant is given by Equation 1.2, D = vd . The fact that Xenon atoms are heavier
2
won’t affect the distance between collisions very much, but the fact that they are slower means the diffusion
constant will be smaller for Xenon.
ASSESS: It is intuitive that a heavy, slow-moving thing will spread more slowly than a light, fast-moving
thing.
Q1.3 REASON: We know that higher temperature indicates faster molecular motion on a microscopic scale. So, we
expect diffusion to be faster in hot water than in cold water. This means the diffusion constant will be larger
for hot water.
ASSESS: This can be seen easily by putting drops of food coloring or other dyes into glasses of water with
different temperatures.
Q1.4 REASON: One reason might be that the elephant trunk snake is larger. The surface area of skin available for
gas exchange scales with  × r (treating the snake as cylindrical). The volume available for lungs scales with

 × r 2 . So as snake size increases, the surface area increases linearly with r , whereas the volume increases

quadratically in r , meaning V ∝ r 2 . Thus, as snake size increases, volume increases faster than surface area,
and using the volume for lungs becomes more efficient than using the skin for gas exchange.
ASSESS: This is not the only possible reason. A larger snake may also have a thicker skin, such that diffusion
of gases through the skin would take longer for the larger snake.




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