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Organic Chemistry notes

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  • January 30, 2024
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Nucleophilic Addition
Nucleophilic Substi tuti on in Biochemistry

Biosynthesis of S- adenosylmethionine (SAM):




Nucleophilic Substi tuti on at Saturated Carbon

Nucleophile- Friend of positive charges
- highly electronegative atom charged NEGATIVE- one of its pair of electrons will attack some who has
positive density charge

Electrophile- Friend of negative charges
- C atom who had density positive charge and good leaving group




1) Nucleophile adds first, then leaving group departs- Impossible
a. Impossible since intermediate stage including pentavalent
carbon (5 bonds- 10 bonding shell (shared) electrons) would be
involved
2) Leaving group departs first, then nucleophile adds- Possible- SN1
The nucleophile

S Na
mechanism
Leaving
a. Two step mechanism H H
Cl
Group
Departs
H + Cl
S

i. Step 1: Leaving group departs- SLOW H
Nucleophile
Arrives
H H


ii. Step 2: Nucleophile arrives- FAST The electrophile Intermediate
Carbocation
+ Na


b. Rate of reaction depends only on [PhCH2Cl] and rate
isn’t increased by increasing [nucleophile] – step involving PhCH2Cl is rate determining- STEP 1
c. Rate determining step is unimolecular- electrophile only- mechanism is SN1
bonds partly
3) Nucleophile arrives whilst leaving group departs- The nucleophile formed/broken

Possible- SN2 mechanism S
H H
Nucleophile
Arrives - H H -
AND S Cl
a. One-step mechanism: +
Cl Transition state
Electrophile
i. Rate is dependent on both [nucleophile] Na
The electrophile
Departs


and [electrophile]
b. Rate determining step is biomolecular-
S
electrophile and nucleophile- mechanism is SN2
+ Cl + Na
Deciding which Mechanism occurs:

 There are two possibilities- SN1 and SN2

,  Many factors control which mechanism occurs but one of main factors is structure of
ELECTROPHILE X
X is the leaving group
Methyl Primary Secondary Tertiary


Electrophile H H H H R H R R
Structure H X R X R X R X
If R = alkyl H H R R

SN1 No ? H H R H R H R R
No Yes

SN2 Yes Yes ? No carbocation stability increases



 SN1 is favoured for ELECTROPHILE that form stable carbocation intermediate
 SN2 is favoured for ELECTROPHILE that has fewer ‘R groups’ since these hinder attack by nucleophile-
STERIC HINDRANCE

Stereochemistry and Substi tuti on

Consider SN2 mechanism:




 Nucleophile approaches on opposite side of electrophile to side where leaving group is departing
 Stereochemistry of tetrahedral carbon
where substitution has occurred is
INVERTED in product
o Leads to inversion of
configuration for chiral electrophile The nucelophile can add
to either face of the flat
carbocation
+ Br Me
Consider SN1 mechanism:
Br

 SN1 leads to RACEMIC MIXTURE of products leaving group
PLANAR
carbocation
Ph
Et
departs


CH3 CH3
H3C S + Br S AND S S
CH3



(S)-enantiomer (R)-enantiomer
50% 50%



Selecti vity in Nucleophilic Substi tuti on

 Several possible ‘leaving groups’- can accept electron pair from breaking bond
 If a molecule contains two possible sites for nucleophilic substitution- i.e. two possible leaving groups
(how can we predict at which site of reaction will occur?)
H3C S
O Path B
Path A
O Br

O
S Br O S
O
+ + Br
O
bromide ion
carboxylate ion

 Stability of anion product of leaving group- plays important role in control of rate of reaction
o e.g. Carboxylate or Bromide

, o
Steric hindrance to nucleophilic attack in SN2 and Carbocation stability in SN1- important factors
along with specific reaction conditions used
 Compare two reactions in which leaving group differs- Which is fastest?




 Anion product is formed from leaving group in rate determining step of SN1 and SN2 reaction
o So, Fastest reaction- is the one in which more stable anion (e.g. Bromide or Carboxylate) is formed
 Compare stability of two anions by comparing acidity of HBr with CH 3CO2H:




 Stronger acids- have lower pKa value
o HBr is stronger acid than CH3CO2H
o HBr is more dissociated – equilibrium is more to
LEFT
 Br- ion is more stable anion
 Anions from strong acids are STABLE – tend to make
good leaving groups

Substi tuti on of Alcohols

 HO- is very poor leaving group- H2O is weak acid with pKa= 16

OH Cl + HO


Cl


 But H2O is very good leaving group- H3O+ is strong acid
with pKa=-1.7
o So nucleophilic substitution of alcohols REQUIRES
protonation of oxygen to take place first

Comparing Nucleophiles- DELOCALISATION

 Species is MORE STABLE- LESS REACTIVE- of multiple
resonance forms are shown
 Nucleophilic strength is DECREASED – if nucleophilic
lone pair can be shared by multiple electronegative
atoms- DELOCALISATON

Comparing Nucleophiles- ELECTRONEGATIVITY

 Amines are more nucleophilic than Alcohols
o Oxygen is more electrophilic than Nitrogen
SLOWER
o Outer shell electrons are held more tightly by Oxygen H H
H
O H O
H Br
OH H H
than by Nitrogen H H
+ Br
- HBr H

o Oxygen lone pair electrons are LESS AVAILABLE to
participate in Substitution reactions FASTER
H H
H H H
H N H N
NH2 Br H H
+ Br
H H - HBr H

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