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AAMC FL 5 Exam with correct Answers
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AAMC FL 5 Exam with correct Answers
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AAMC FL 5 Exam with correct AnswersQuestion 6 - Answer- Thought process:
- Didn't know the structure of flavin, therefore needed to narrow down answer from answer choices:
- Knew A was a pyrimidine, cross that out - Had not seen structure of B before - Knew C was ubiquinone (still chose just because ubiquinone was mentioned in the passage (stupid))
- Didn't try and analyze structure of D at the time Correct thought process:
- Cross out A bc pyrimidine - Never seen B before (come back to later)
- Cross out C because ubiquinone - Cross out D because histidine - Therefore, left with correct answer B
Two open flasks I and II contain different volumes of the same liquid. Suppose that the pressure is measured at a point 10 cm below the surface of the liquid in each container. How will the pressures compare?
A.
The pressures will be equal.
B.
Pressure in flask I will be less.
C.
Pressure in flask II will be less.
D.
The pressures cannot be compared from the information given. - Answer- Not sure how I missed this one, even wrote out the equation during the exam. Need to pay more attention to what I'm doing when answering
If all else is held constant, which of the following changes would NOT double the volume of a gas?
A.
Doubling the pressure
B.
Doubling the absolute temperature
C.
Halving the pressure
D. Doubling the number of gas molecules - Answer- Got lazy and didn't work out all answer
choices
What is the number of neutrons in the nucleus of the atom used to produce laser radiations?
A.
48
B.
49
C.
50
D.
51 - Answer- Concept:
- Ions do not lost protons - Ions only lose ELECTRONS
Approximately how many moles of Kr+ are contained in the laser tube at 0°C and 1 atm?
A.
3 x 10-7
B.
2 x 10-6
C.
4 x 10-5
D.
5 x 10-4 - Answer- Define STP Conditions: 1 atm, 0C
- If constants aren't given you don't need to solve problem, but can help to know - I missed this problem because I didn't read the passage close enough at first, which gave me the volume I needed to solve the problem
The radiation of wavelength 605 nm CANNOT be used to produce the fluorescence radiations depicted in Figure 3 because:
A.
the energy of the absorbed radiation must be larger than the energy of the fluorescence radiation.
B.
the energy of the absorbed radiation must be smaller than the energy of the fluorescence radiation.
C.
the 605-nm radiation has more energy than the 407-nm radiation.
D.
the 605-nm radiation is not visible. - Answer- HAVE TO READ THE PASSAGE CLOSELY - sometimes I get caught up in thinking I can rationalize an answer choice from outside conceptual knowledge when it's impossible - it literally states almost word for word in the passage the answer
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