Behaalde 16/20 met deze samenvatting, hiervan 9/10 op het theoriegedeelte, de oefening was minder xd. Alles staat in volgorde van de lessen, op het einde alle (tot 2020) uitgewerkte theorievragen van vorige jaren.
............
nodiga E
zelfde grafien bij
geleidende bol MAAR
volle
:
1
: S Bij volle insulator
I S
r R ↑
R
, Potential
Elektrische
VB-Va =
-d .
Nukunnen we Eoon in (/m) zetten
Vb
. Uniform veld
- x(m)
↳
B
VA =
V Va - =
Ov Wan de
..... y C ...
= - -.
- - - - - -
..............I S
"
di
+
-
[
·
VBc = Vc -
VB = -
SE - = -
-
4
,
2
m
.
dx = -
v
A B
L
I C
-
3
O i x /m) Vac =
Vc Va -
=
VAB + VBc = v
(conservatief weld)
Vb Holle geleidende bol
.
E
a
-
~ Want als je tussen en V bereuent krijg je 0
YTE dus Verandering
-
............ :
= O
D
-
: S
:
I S
r R r R
Vb . Puntlading
F
~
E E =
=%
4
B0
An
9
&
+ r
-
A
L ~I
V
↑B rB
B- 9
JE d) S 1 dr
SE
d
VB Va
-
=
=
-
- = .
.
4/1 r2
A PA
(1 del
:
-
1
.
9 .
F1 s
-Va = 30 Pl -
Stel we kiezen = 00 als referentie
dan is V = 0
9 in 3 dimensies
= VB =
D
E B D
Vb Stelsel .
Puntlading
b b
I I I I
+ & & -
+9 A B -
9 Bepaal V =
VB-VA
I I
d
Superpositie :
VV Va Lelfde referentie V(00) = O
9
Epot
1
Av 9
-
=
= .
(a-b
> Av vB va y3 (3 ab (5 a 8)
-
= =
+
-
+
-
1 2b-d
1= AV =
29.
·
.
43 (d b) b
-
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