100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Solutions Manual for Chemistry 10th Edition By Raymond Chang (All Chapters, 100% Original Verified, A+ Grade) $20.49   Add to cart

Exam (elaborations)

Solutions Manual for Chemistry 10th Edition By Raymond Chang (All Chapters, 100% Original Verified, A+ Grade)

 52 views  1 purchase
  • Course
  • Chemistry 10th Edition By Ray
  • Institution
  • Chemistry 10th Edition By Ray

This Is Original 10th Edition of Solutions Manual From Original Author. All Other Files in the market are fake/old Edition. Other Sellers Have changed old Edition Number to new But solutions Manual is old Edition. Solutions Manual for Chemistry 10th Edition By Raymond Chang (All Chapters, 100% O...

[Show more]

Preview 4 out of 696  pages

  • May 20, 2024
  • 696
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers
  • Chemistry 10th Edition By Ray
  • Chemistry 10th Edition By Ray
avatar-seller
tutorsection
CHAPTER 1 CHEMISTRY: THE STUDY OF CHANGE Problem Categories Biological : 1.24, 1.48, 1.69, 1.70, 1.78, 1.84, 1.93, 1.95, 1.96, 1.97, 1.105. Conceptual : 1.3, 1.4, 1.11, 1.12, 1.15, 1.16, 1.54, 1.62, 1.89, 1.101, 1.103. Environmental : 1.70, 1.87, 1.89, 1.92, 1.98. Industrial : 1.51, 1.55, 1.72, 1.81, 1.91. Difficulty Level Easy : 1.3, 1.11, 1.13, 1.14, 1.15, 1.21, 1.22, 1.23, 1.24, 1.25, 1.26, 1.29, 1.30, 1.31, 1.32, 1.33, 1.34, 1.54, 1.55, 1.63, 1.64, 1.77, 1.80, 1.84, 1.89, 1.91. Medium : 1.4, 1.12, 1.16, 1.35, 1.36, 1.37, 1.38, 1.39, 1.40, 1.41, 1.42, 1.43, 1.44, 1.45, 1.46, 1.47, 1.48, 1.49, 1.50, 1.51, 1.52, 1.53, 1.56, 1.57, 1.59, 1.60, 1.61, 1.62, 1.70, 1.71, 1.72, 1.73, 1.74, 1.75, 1.76, 1.78, 1.79, 1.81, 1.82, 1.83, 1.85, 1.94, 1.95, 1.96, 1.97, 1.98. Difficult : 1.58, 1.65, 1.66, 1.67, 1.68, 1.69, 1.86, 1.87, 1.88, 1.90, 1.92, 1.93, 1.99, 1.100, 1.101, 1.102, 1.103, 1.104, 1.105, 1.106. 1.3 (a) Quantitative. This statement clearly involves a measurable distan ce.
(b) Qualitative. This is a value judgment. There is no numerical scale of measurement fo r artistic
excellence.
(c) Qualitative. If the numerical values for the densities of ice and water were given, it would be a
q
uantitative statemen t.
(d) Qualitative. Another value judgmen t.
(e) Qualitative. Even though numbers are involve d, they are not the result of measurement.
1.4 (a) h ypoth esis (b) law (c) th eory
1.11 (a ) Chemical property. Oxygen gas is consumed in a combustion reaction; its composition and identity are changed. (b) Chemical property. The fertilizer is consumed by the growing plants; it is turned into vegetable ma tter
(d
ifferent composition) .
(c) Physical property. The measurement of the boiling point of water does not change its identity or
composition.
(d) Physical property. The measurement of the densities of lead and aluminum does not change th eir
com
position.
(e) Chemical property. When uranium undergoes nucl ear decay, the products are chemically differen t
substances .
1.12 (a) Physical change. The helium isn't changed in any way by leaking out of the balloon. (b) Chemical change in the ba ttery.
(c) Physical change. The orange juice concentrate can be regenerated by evaporation of the water.
(d) Chemical change. Photosynthesis changes water, carbon dioxide, etc., into complex organic matte r.
(e) Physical change. The salt can be recovered unchanged by evaporatio n.Chemistry 10e Raymond Chang (Solutions Manual All Chapters, 100% Original Verified, A+ Grade) CHAPTER 1: CHEMISTRY--THE STUDY OF CHANGE 2 1.13 Li, lithium; F, fluorine; P, phosphorus; Cu, copper ; As, arsenic; Zn, zinc; Cl, chlorine; Pt, platinum; Mg, magnesium; U, uranium; Al, aluminum; Si, silicon; Ne, neon. 1.14 (a) K (b) Sn (c) Cr (d) B (e) Ba
(f
)Pu (g
)S (h) Ar (i) Hg
1.15 (a) ele ment (b) com pound (c) ele ment (d) com pound
1.16 (a) hom ogeneous mixture (b) elem ent (c) com pound
(d) hom
ogeneous mixture (e) heterogeneous mixture (f) hom
ogeneous mixture
(g) het
erogeneous mixture
1.21 mass 586 g
volume 188 mL=== density 3.12 g/mL
1.22 Strategy: We are given the density and volume of a liquid and asked to calculate the mass of the liquid. Rearrange the density equation, Equation (1.1) of the text, to solve for mass. massdensityvolume=
Solution: mass = density × volume 0.798 g17.4 mL1m L=×= mass of ethanol 13.9 g
1.23 5C?C = ( F 3 2 F )9F°°° − ° ×° (a)5C?C = ( 9 5 3 2 ) F9F°°− ° × =°35 C° (b)5C? C=( 1 2 3 2 )F9F°°− ° × =°11 C−°
(c)5C? C = (102 32) F9F°°− ° × =°39 C°
(d)5C? C = (1852 32) F9F°°− ° × =°1011 C°
(e) 9F?F C 3 2 F5C°⎛⎞°=°× +°⎜⎟°⎝⎠
9F? F 273.15 C 32 F5C° ⎛⎞°=− °× + °=⎜⎟° ⎝⎠459.67 F−°
1.24 Strategy: Find the appropriate equations for converting between Fahrenheit and Celsius and between Celsius and Fahrenheit given in Section 1.7 of the te xt. Substitute the temperature values given in the problem into the appropriate equation. (a) Co nversion from Fahrenheit to Celsiu s.
5C?C = ( F 3 2 F )9F°°° − ° ×° CHAPTER 1: CHEMISTRY--THE STUDY OF CHANGE 3 5C=( 1 0 5 3 2 )F9F°−° × =°?C 4 1 C°° (b) Conversion from Celsius to Fahrenheit. 9F?F C 3 2 F5C°⎛⎞°=°× +°⎜⎟°⎝⎠ 9F11.5 C 32 F5C° ⎛⎞=− °× + °=⎜⎟° ⎝⎠? F 11.3 F°° (c) Conversion from Celsius to Fahrenheit. 9F?F C 3 2 F5C°⎛⎞°=°× +°⎜⎟°⎝⎠ 3 9F6.3 10 C 32 F5C° ⎛⎞=× ° × + ° =⎜⎟° ⎝⎠4?F 1 . 1 1 0 F°× ° (d) Conversion from Fahrenheit to Celsius. 5C?C = ( F 3 2 F )9F°°° − ° ×° 5C= (451 32) F9F°−° × =°? C 233 C°° 1.25 1KK( C 2 7 3 C )1C=°+ °° (a) K = 113°C + 273°C = 386 K (b) K = 37°C + 273°C = 3.10 × 102 K (c) K = 357°C + 273°C = 6.30 × 102 K 1.26 (a) 1KK( C 2 7 3 C )1C=°+ °° °C = K − 273 = 77 K − 273 = −196°C (b) °C = 4.2 K − 273 = −269°C (c) °C = 601 K − 273 = 328°C 1.29 (a) 2.7 × 10−8 (b) 3.56 × 102 (c) 4.7764 × 104 (d) 9.6 × 10−2 1.30 (a) 10−2 indicates that the decimal point mu st be moved two places to the left. 1.52 × 10−2 = 0.0152 (b) 10−8 indicates that the decimal point must be moved 8 places to the left. 7.78 × 10−8 = 0.0000000778 CHAPTER 1: CHEMISTRY--THE STUDY OF CHANGE 4 1.31 (a) 145.75 + (2.3 × 10−1) = 145.75 + 0.23 = 1.4598 × 102 (b) 4
2279500 7.95 10=
2.5 10 2.5 10×=
××23.2 10× (c) (7.0 × 10−3) − (8.0 × 10−4) = (7.0 × 10−3) − (0.80 × 10−3) = 6.2 × 10−3 (d) (1.0 × 104) × (9.9 × 106) = 9.9 × 1010 1.32 (a) Addition using scientific notation. Strategy: Let's express scientific notation as N × 10n. When adding numbers using scientific notation, we must write each quantity w ith the same exponent, n. We can then add the N parts of the numbers, keeping the exponent, n, the same. Solution: Write each quantity with the same exponent, n. Let’s write 0.0095 in such a way that n = −3. We have decreased 10n by 103, so we must increase N by 103. Move the decimal point 3 places to the right. 0.0095 = 9.5 × 10−3 Add the N parts of the numbers, keeping the exponent, n, the same. 9.5 × 10−3 + 8.5 × 10−3 18.0 × 10−3 The usual practice is to express N as a number between 1 and 10. Since we must decrease N by a factor of 10 to express N between 1 and 10 (1.8), we must increase 10n by a factor of 10. The exponent, n, is increased by 1 from −3 to −2. 18.0 × 10−3 = 1.8 × 10−2 (b) Division using scientific notation. Strategy: Let's express scientific notation as N × 10n. When dividing numbers using scientific notation, divide the N parts of the numbers in the usual way. To come up with the correct exponent, n, we subtract the exponents. Solution: Make sure that all numbers are expressed in scientific notation. 653 = 6.53 × 102 Divide the N parts of the numbers in the usual way. 6.53 ÷ 5.75 = 1.14 Subtract the exponents, n. 1.14 × 10+2 − (−8) = 1.14 × 10+2 + 8 = 1.14 × 1010 (c) Subtraction using scientific notation. Strategy: Let's express scientific notation as N × 10n. When subtracting numbers using scientific notation, we must write each quantity with the same exponent, n. We can then subtract the N parts of the numbers, keeping the exponent, n, the same.

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller tutorsection. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $20.49. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

79271 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$20.49  1x  sold
  • (0)
  Add to cart