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MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024 (792287) - DUE 22 July 2024
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MIP1501 Assignment 3 (COMPLETE ANSWERS) 2024(792287) - DUE 22 July 2024
Question 1 (26) 1.1. Solve and explain each step to grade
6 mathematics learners the following multiplication and
division calculations involving fractions.
1.1.1. 684÷ 612 (6)
1.1.2. 714× 418 (4)
1.1.3. 316× 624 (6)
1.1.4. 817÷ 124 (4)
1.2. Modelling refers to the idea that learners build in
their minds and play out with objects or in picture form
on paper sometimes to solve problems. Give and explain
For assistance whatsapp +254702715801
,at least three benefits that you may achieve in your
primary mathematics class by employing modelling. (6)
1.1 Multiplication and Division Calculations Involving
Fractions
1.1.1. 684÷612\frac{68}{4} \div \frac{61}{2}468÷261
1. Rewrite the division as multiplication by the
reciprocal:
684÷612=684×261\frac{68}{4} \div \frac{61}{2} =
\frac{68}{4} \times \frac{2}{61}468÷261=468×612
2. Simplify the fractions if possible:
684=17and261 stays the same\frac{68}{4} = 17 \quad
\text{and} \quad \frac{2}{61} \text{ stays the same}468
=17and612 stays the same
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, 3. Multiply the numerators and the denominators:
17×2=3417 \times 2 = 3417×2=34 1×61=611 \times 61 =
611×61=61
4. Simplify the resulting fraction (if possible):
3461 (This fraction is already in its simplest form.)\frac{34
}{61} \text{ (This fraction is already in its simplest
form.)}6134 (This fraction is already in its simplest form.)
So, 684÷612=3461\frac{68}{4} \div \frac{61}{2} =
\frac{34}{61}468÷261=6134.
1.1.2. 714×418\frac{71}{4} \times \frac{41}{8}471×841
1. Multiply the numerators together:
71×41=291171 \times 41 = 291171×41=2911
2. Multiply the denominators together:
For assistance whatsapp +254702715801
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