1. The following equation is correct: 10cos(2À6t0) = 10sin(120Àt + À/2)
True/False: True
2. Given the following parameters, select the correct equation for the ampli- tude modulated
(AM) carrier signal. Am=3v, Ac=3v, fm=5500Hz, fc=100MHz,
Æm=0, Æc=0
a. s(t) = 3[1+1.08 cos(2À550t0)] cos(2À10E06t)
b. s(t) = 3[1+1cos(2À550t0)] cos(2À10E06t)
c. s(t) = 3[1+6.5 cos(2À350t0)] cos(2À10t0)
d. s(t) = 6.5[1+0.93 cos(2À10t0)] cos(2À10E03t): b. s(t) = 3[1+1cos(2À550t0)] cos(2- À10E06t)
3. Given the following AM modulated signal, determine the occupied frequen- cy bandwidth
(note: assume double-sideband large carrier (DSB-LC):
s(t) = 3[1+0.5 cos(2À250t0)] cos(2À10E09t)
a. Frequency bandwidth = 2500 Hz
b. Frequency bandwidth = 2.5 kHz
c. Frequency bandwidth = 5 kHz
d. Frequency bandwidth = 200 GHz: c. Frequency bandwidth = 5 kHz
4. Select the correct statement(s) regarding amplitude modulation (AM).
a. If the AM Index is greater than 1 (i.e., µAM>1), then over modulation occurs leading to signal
distortion
b. With AM, the message is captured as amplitude changes to the carrier's amplitude.
c. The AM modulated carrier bandwidth is dependent upon the baseband signal's
frequency bandwidth
d. All of the above are correct: d. All of the above are correct
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, IT 300 Homework 2 | Questions and Answrs 2024
5. What are the units of the FM Kvco?
a. radians per Hertz
b. Hertz per volt
c. volts per Hz
d. Hertz per radians: b. Hertz per volt
6. Given the following AM modulated signal, determine the original message, m(t):
s(t) = 5[1+0.5 cos(2À10t0)] cos(2À16E06t)
a. m(t) = 2.5cos(2À16M0 Hz*t)
b. m(t) = 5cos(2À16E06t)
c. m(t) = 2.5cos(2À10t0)
d. m(t) = 5cos(2À10t0): c. m(t) = 2.5cos(2À10t0)
7. Given the following PM modulated signal equation, determine the frequency bandwidth.
s(t)=1cos(2À1E29t + 2cos(2ÀE13t))
a. 2 kHz
b. 6 kHz
c. 24 kHz
d. 116 kHz: b. 6 kHz
8. Given the following message, m(t), carrier, c(t), and Kp=0.1(rad/v), deter- mine the PM
modulated signal equation and PM index. m(t)=2cos(2À400t0), c(t)=4cos(2ÀM8 Hzt).
a. s(t)=4cos(2ÀE46t + 0.75cos(2À350t0)), µPM=0.75
b. s(t)=4cos(2ÀE86t + 0.2cos(2ÀE43t)), µPM=0.2
c. s(t)=3cos(2ÀE46t + 0.75cos(2À350t0)), µPM=0.75
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