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CS6515 - ALGORITHMS- EXAM 1 QUESTIONS AND ANSWERS 2024

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CS6515 - ALGORITHMS- EXAM 1 QUESTIONS AND ANSWERS 2024

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  • August 18, 2024
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  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • CS6515 - ALGORITHMS
  • CS6515 - ALGORITHMS
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CS6515 - ALGORITHMS- EXAM 1

Steps to solve a Dynamic Programming Problem - ANSWERS-1. Define the Input
and Output.



2. Define entries in table, i.e. T(i) or T(i, j) is...



3. Define a Recurrence relationship - Based on a subproblem to the main
problem. (hint: use a prefix of the original input 1 < i < n).



4. Define the Pseudocode.



5. Define the Runtime of the algorithm. Use Time Function notation here => T(n) =
T(n/2) + 1...



DP: Types of Subproblems (4) - ANSWERS-Input = x1, x2, ..., xn

1) Subproblem = x1, x2, ..., xi ; O(n)

2) Subproblem = xi, xi+1, ..., xj ; O(n^2)



Input = x1, x2, ..., xn; y1, y2, ..., ym

1) Subproblem = x1, x2, ..., xi; y1, y2, ..., yj ; O(mn)

,Input = Rooted Binary Tree

1) Subproblem = Smaller rooted binary tree inside the Input.



DC: Geometric Series - ANSWERS-Given r = common ratio and a = first term in
series

=> a + ar + ar^2 + ar^3 + ... + ar^(n-1)



=> a * [(1 - r^n) / (1-r)]



DC: Arithmetic Series - ANSWERS-Given d = common difference and a = first term
in series => a + (a + d) + (a + 2d) + ... + (a + (n-1)d



Sum = n/2 * [2*a + (n-1)d]



DC: Solving Recurrences - Master Theorem - ANSWERS-If T(n) = aT([n/b]) + O(n^d)
for constants a>0, b>1, d>=0:



T(n) = {

O(n^d) if d > logb(a)

O((n^d)logn) if d = logb(a)

O(n^(logb(a))) if d < logb(a)

}

, Nth roots of Unity - ANSWERS-(1, 2*PI*j/n) for j = 0, 1, ..., n-1

*Around the Unit Circle!



Steps to solve for FFT - ANSWERS-1) Write out Matrix Coefficient Form based on n
(size of input) Mn(w) = [ 1 1 ... 1

1 w ... w^n-1

...

1 w^n-1 ... w^((n-1)*(n-1)) ]



2) Find value for w = e^(2*PI*i)/n, Substitute in Mn(w).



3) For the input coefficients into nx1 matrix. I.E. [4 0 1 1], let known as B.



4) Evaluate FFT:

a) FFT of Input = Mn(w) x B

b) Inverse FFT of Input = 1/n * Mn(w^-1) x B



Euler's Formula - ANSWERS-e^ix = cosx + isinx



Imaginary Number Multiples - ANSWERS-i = i, i^2 = -1, i^3 = -i, i^4 = 1

i = -i, i^2 = -1, i^3 = i, i^4 = 1

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