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Elevator Mechanic Exam with complete solutions
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Elevator Mechanic Exam 2024-2025 withcomplete solutions
A nnLatching nnrelay: nnUsed nnfor nncall nnregistration,direction nnselection nnor nnas nnselector nnrelays
Two nntypes nnare: nnSet/Rest nnare nnelectrical nnand nnMechanical nnLatching nnrelays nn
Need nnto nnknow nnlatching nnrelay nnsymbol, nnIts nna nnbox nnwith nnshaded nntriangle nnin nnlower nnright nnhand
nncorner. nn- nncorrect nnanswer-Which nnrelay nndo nnyou nnneed nnto nnOrder
710 nnPg, nn7
RPM nn= nn60 nn∙ nnƒ nn÷ nnP÷2 nn=
Step nn1. nn60 nnx nnFrequency nn(Hz.) nn= nn
Step nn2. nnPoles nn÷ nn2 nn=
Take nnanswer nn1 nnand nn÷ nnby nnanswer nn2 nn= nn- nncorrect nnanswer-Know nnthe nnformula nnfor nnRPM
435 nnPg. nn5
If nnyou nnare nnreferring nnto nna nnmegohm nnmeter, nnit nnis nna nntest nnof nnthe nninsulation nnproperties nnof nnsuch
nnthings nnas nnelectric nnwiring, nnmotor nnwindings nnand nnhigh nnpower nnantenna nnmounts. nn
We nnuse nna nn"megger" nnor nn"meg nnout" nnelectrical nnwiring nnand nnequipment nnto nnsee nnif nnit nnis nnshorted nnto
nnground nnor nnthe nnframe nnin nnany nnway. nn
The nnmegger nnuses nnmuch nnhigher nnvoltages nnto nncheck nnresistance nnthan nna nnnormal nnVolt-ohm nnmeter. nn
Minimum nnresistance nnis nn1 nnMeg nnOhm nn- nncorrect nnanswer-Know nnwhat nna nnMegger nnis nnand nnwhat nnit
nndoes
636 nnPg. nn13
,(1) nnA nnparallel nnconnection. nn(2) nnA nnresistive nnelement nnplaced nnacross nnthe nnterminals nnof nnan nnarmature
nnto nnbypass nna nnportion nnof nnthe nncurrent. nn(3) nnA nnflexible nnelectrical nnconductor nndesigned nnto nnconduct
nncurrent nnaround nnthe nnmechanical nnjoint nnbetween nntwo nnconductors. nn(4) nnThe nnresistive nnelement
nn(Usually nnof nnvery nnlow nnresistance) nnused nnin nnparallel nnwith nna nnDC nnammeter nnmovement nnto nnbypass nna
nncalibrated nnportion nnof nnthe nntotal nncircuit nncurrent. nn- nncorrect nnanswer-Shunt nnOverloads
425 nnAll nnPages
Bad nnGround nn- nncorrect nnanswer-You nnare nnusing nna nnTemp nnRun nnBox nnand nnyou nnget nnshocked! nnWhy!
520 nnPg. nn4
The nnbridle nnhitch nncan nnconsist nnof nntwo,three, nnor nnfour nnsingle nnhitches nn(fig. nn3-22), nnused nntogether nnto
nnform nna nnbridle nnhitch nnfor nnhoisting nnan nnobject
A nnsling nnwith nntwo nnlegs nnused nnto nnlift nna nn1,000 nnpound nnobject nnwill nnhave nn500 nnpounds nnof nnthe nnload
nnon nneach nnleg nnwhen nnthe nnsling nnangle nnis nn90 nndegrees. nnThe nnload nnstress nnon nneach nnleg nnincreases nnas
nnthe nnangle nndecreases; nnand nnif nnthe nnsling nnangle nnwas nn30 nndegrees nnlifting nnthe nnsame nn1,000 nnpound
nnobject, nnthe nnload nnwill nnbe nn1,000 nnpounds nnon nneach nnleg. nnTry nnto nnkeep nnall nnsling nnangles nngreater
nnthan nn45 nndegrees; nnsling nnangles nnapproaching nn30 nndegrees nnare nnconsidered nnextremely nnhazardous
nnand nnmust nnbe nnavoided nnat nnall nncost. nn- nncorrect nnanswer-Bridal nnHitch
128 nnPg nn17
Scaffolding nnshould nnbe nntied nnto nnthe nnstructure nnusing
#9 nnwire nnor nntie-in nndevices. nnThe nnfirst nnvertical nntie
should nnbe nnat nnthe nnmaximum nnheight nnof nn4 nntimes nnthe
narrowest nnbase nndimension. nnAdditional nnties nnare nnnot
to nnexceed nn26' nnvertically. nnMaximum nnhorizontal
distance nnbetween nnties nnis nnnot nnto nnexceed nn30'. nn- nncorrect nnanswer-Scaffolding, nnYou nnhave nn32' nnof
nnrise, nnyou nnare nnusing nn3x5 nnscaffolding. nnWhere nnwill nnthe nntie nnoff nnpoints nnbe nn?
140 nnPG. nn287-288
,Counterweights nn(Typically) nnare nnhung nnto nncounter nnbalance nnthe nnweight nnof nnthe nncar nnPLUS nn40% nnof
nnCapacity nnLoad. nn- nncorrect nnanswer-How nnmuch nnshould nnCounterweight nnway?
240 nnPg. nn14
Note: nnWe nndo nnnot nnuse nnwire nnsmaller nnthan nn#20 nnin nntravelling nncables nnand nn#24 nnoutside nntravelers.
Largest nnwires nnare nnfeeders nnto nnHoist nn/Pump nnmotor
We nnalways nnhave nn10 nn% nnspares
10% nnof nn52 nn= nn5.2
On nna nncalculator nnMultiply nnthe nnpercent nn10 nnby nnthe nnnumber nnyou nnhave nnand nn÷ nnby nn100
10 nnX nn52 nn÷ nn100 nn= nn5.2 nn- nncorrect nnanswer-Pulling nnSpare nnWires nn(Example) nn10% nnof nn52 nnWires
515 nnPg.26
The nncorrect nnlube nnmust nnbe nnused nnon nnchains. nn- nncorrect nnanswer-The nnfreight nndoor nnmotor nnis
nnspinning nnbut nnthe nndoor nnwont nnmove, nnWhy?
535 nnPg. nn9
Lula: nnLimited nnuse/Limited nnAccess nn(Example nnWheelchair nnLifts)
Max nnRise nn25'
Max nnSpeed nn30 nnFt/Min
Max nnCapacity nn1400 nnLbs.
Max nnPlatform nnArea nn18 nnSq/Ft.
Residential nnElevator:
Max nnRise nn50 nn'
Max nnSpeed nn40 nnFt/min
Max nnCapacity nn940 nnLbs.
, Max nnPlatform nnArea nn19 nnSq/Ft nn
840 nnPg nn2
Dumbwaiters:
Platform nnlimited nnto nn9 nnSq/Ft
Inside nnheight nnis nnlimited nnto nnno nnmore nnthan nn4 nnFeet
Capacity nnis nnlimited nnto nn500Lbs
No nnRiders nn- nncorrect nnanswer-Read nnLula nnand nnDumb nnwaiters
545 nnPg nn1
You nnnever nnget nnon nntop nnand nnyou nnwork nnonly nnpartially nnin nnwith nnthe nnmain nnline nnOFF nn- nncorrect
nnanswer-If nnyou nnget nnon nntop nnof nnDumbwaiter nnwhat nnmust nnbe nndone?
545 nnPg nn14
Notes:(Pi) nnπ nnis nn3.1416 nnand nn231 nnCubic nninches nnto nnthe nnGallon
Area:
Remember nnto nn÷ nn6" nn÷ nn2 nn= nn3 nnto nnget nnRadius
Area nn= nnπ∙ nnr²
Area nn= nn3.1416 nnx nn3 nnx nn3 nn= nn28.27 nninches nnor nn3.146 nnx nn9 nn= nn28.27
Volume
Multiple nnare nntimes nnheight nnto nnsolve nnfor nnVolume
V nn= nnA∙H
V nn= nn28.27 nnx nn300 nn(25" nnfeet nnx nn12" nn= nn300)
V nn= nn8481 nnCubic nnInches
Since nnwe nnalready nnknow nnthere nnare nn231 nncubic nninches nnto nnthe nngallon nn
8481 nn÷ nn231 nn= nn36.71 nnGallons nn- nncorrect nnanswer-PSI nnFormula nnand nnGallons nn(Example) nnHow nnmuch
nnoil nnto nnmove nna nn6" nnjack nn25'
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