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Clemson Chem 1010 Exam 3 with complete verified solutions(GUARANTEED SUCCESS) $14.99
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Clemson Chem 1010 Exam 3 with complete verified solutions(GUARANTEED SUCCESS)
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  • Chem 1010
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  • Chem 1010

Stoichiometry the mole ratios among the reactants and products in a chemical reaction chemical equation a description of the identities and proportions of reactants and proucts reactants substances consumed during a chemical reaction products substances formed during a ch...

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  • September 2, 2024
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  • 2024/2025
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Clemson Chem 1010 Exam 3 with
complete verified
solutions(GUARANTEED SUCCESS)
Stoichiometry - answer the mole ratios among the reactants and products
in a chemical reaction


chemical equation - answer a description of the identities and proportions
of reactants and proucts


reactants - answer substances consumed during a chemical reaction


products - answer substances formed during a chemical reaction


molecular mass - answer the mass in amu of one molecule of a molecular
compound


molar mass - answer the mass of one mole of a substance


formula mass - answer mass in amu of one formula unit of a compound


law of conservation of mass - answer the principle that the sum of the
masses of the reactants in a chemical reaction is equal to the sum of the
masses in the products


percent composition - answer the composition of a compound expressed in
terms of the percentage by mass of each element of the compound


empirical formula - answer a formula showing the smallest whole number
ratio of elements in a compound

, limiting reactant - answer a reactant that is consumed completely in the
chemical reaction. the amount of product depends on this.


theoretical yield - answer max amount of product possible in a chemical
reaction for given quantities of reactants


percent yield - answer ratio, expresse as a percentage of the actual yield
to the theoretical yield


PERCENT YIELD EQUATION - answer (actual) / (theoretical)


x 100


moles to grams - answer ( moles given )
x (grams per mole) = grams


grams to moles - answer (grams given)
x (moles per gram) = moles


chemical formula to atoms - answer use moles!
(moles)
x (atoms per mole..avo's number)


determine limiting and excess reagent - answer 1. grams of a
2. to moles of a available
3. to moles of b needed
4. grams of b to moles of b available
5. compare
6. moles of product + moles of excess....USE TO FIND grams of product
and grams of excess

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