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26401 Load Calculations - Feeders and Services Exam Questions And Accurate Answers $12.99   Add to cart

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26401 Load Calculations - Feeders and Services Exam Questions And Accurate Answers

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26401 Load Calculations - Feeders and Services Exam Questions And Accurate Answers...

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  • September 13, 2024
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  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • 26401 Load Calculations - Feeders and Services
  • 26401 Load Calculations - Feeders and Services
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26401 Load Calculations - Feeders and Services 2024-2025 Exam
Questions And Accurate Answers



Load calculated at 2 circuit 1500VA. - Answer Small Appliance Ciruit



Voltage drop formula 1

VD = (2*L*R*I)/1,000 - Answer VD = voltage drop (in volts)

L = load center or total length in feet

R = conductor resistance per NEC Chapter 9, Table 8

I = current

The number 1,000 represents 1,000' or less of conductor.



Show window loads should be calculated at _____ per linear foot of show window. -
Answer 200VA



What is the minimum demand for that part of a feeder which serves 30' of show windows?

6,000 VA

5,400 VA

3,000 VA

2,700 VA - Answer ft x va = va

30ft x 200VA = 6,000VA

NEC 220.14(C)(2)

At 200 Volt-amperes per linear 300 mm (1 ft) of show window



Voltage drop formula 2

VD = (2*L*K*I)/CM - Answer VD = voltage drop

, L = load center or total length in feet



K= constant (12.9 for copper conductors; 21.2 for aluminum conductors)



I = current

CM= area of the conductor in circular mils (from NEC Chapter 9, Table 8)



Feeder conductor size is adjusted when?

The load supplied is a continuous-duty load.

More than three current-carrying conductors are in a raceway.

The ambient temperature surrounding conductors exceeds temperature ratings.

Voltage drop exceeds 3% for feeders or 5% for the combination of the feeder and branch
circuit.

All of the above - Answer All of those above



In calculating feeder-circuit conductors, if noncontinuous loads equal 450 amperes and
continuous loads equal 550 amperes, what is the total calculated feeder load that the
conductors must handle?

A. 1137.50 amperes

B. 1100 amperes

C. 950 amperes

D. 1317.50 amperes - Answer In order to calculate the total feeder load, you must add
100% of noncontinuous loads to 125% of continuous loads.

450 + (1.25 × 550) = 1137.50 amperes



For a tap from a 400A, 480V, 3Phase feeder, using the 25' tap rule, what is the minimum
size copper THWN conductor required?

1/0

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