Exam (elaborations)
BCH 403 Final Exam Questions Solved 100% Correct | Latest Update
- Course
- Institution
BCH 403 Final Exam Questions Solved 100% Correct | Latest Update
[Show more]
Seller
Follow
Content preview
BCH 403 Final Exam QuestionsSolved 100% Correct | Latest Update
The delta H contributions that lead to the formation of a lipid bilayer include Van
der wwals interactions and hydrogen bonding - Answer true
In the signal hypothesis, a defected signal peptidase would result in membrane
proteins that are instead produced in the cytoplasm - Answer false
Active primary transport requires ATP b/c otherwise, the delta G of the transport
would be positive - Answer True
To be inserted, the alpha helical integral membrane protein requires at least on
helix that is at least 20 residues long and is also amphipathic - Answer True
The glycerophospholipids of a membrane bilayer have been modified to contain
additional Double bonds. This change will likely lower the activation of adenylate
cyclase by a G-protein - Answer False
(PHOTO)
a newly discovered enzyme has two substrates. Substrate 1 is strongly nonpolar and
small. Substrate 2 is strongly nonpolar and large. The kcat/Km for the two enzymes were
discovered to be as follows:
,T or F: A biochemical reaction, without a catalyst or thermodynamic coupling, takes 50
years to reach a state of equilibrium. W/o more information, we cannot make a
determination on either the value of the Keq constant or the positive or negative
value of the DeltaG of the reaction - Answer False
T or F: Due to its small size, the amino acid glycine can be found in tight turns in
a protein structure - Answer True
T or F: The Delta G of a reaction is defined as the energy required to bring the
concentration of reactants and products to equal concentration - Answer False
T or F: One strength of NMR is that it can detect multiple conformations of proteins
and one of its limitations is that proteins must contain certain isotopes - Answer True
T or F: A single residue mutation to an enzyme decreases its rate constant by one half.
This means the reaction now occurs more slowly. - Answer True
T or F: The hydrophobic packing of non-polar residues is thermodynamically favorable
b/c of both the hydrophobic effect and a larger number of weak van der waals -
Answer True
T or F: The classic experiment in which the protein ribonuclease A is first denatured
and reduced, then refolded, was used to demonstrate the role of aromatic residues in
stabilizing covalent disulfide bonds - Answer False
T or F: One reason that we require myoglobin and hemoglobin to store and
transport oxygen is b/c oxygen itself has very poor solubility in water - Answer True
T or F: A mutation in myoglobin that changes the distal histidine into alanine will
result in a lower P50 - Answer False
, The stability of an alpha helix is partly due to hydrogen bonding that occurs between
carbonyl oxygen of one helix and the amino hydrogen of a neighboring alpha helix -
Answer False
Which of the following statements if true regarding the hydrophobic effect - Answer
Non-polar molecules are driven together in order to maximize the entropy of water
The peptide in question 17 is dissolved into a soln that has a pH of 6.5. Under
these conditions, the net charge of the peptide is - Answer +1
A glycine residue is disruptive to the stability of an alpha helix or a beta strand because -
Answer It's R group is too small to participate in stabilizing interactions with neighboring
R groups
With a pKA of 6.37, the carbonic acid/bicarbonate system serves to buffer changes
to the pH of blood. The acid dissociates as follows
H2CO3 + H20 ----> (DOUBLEARROW) HCO3- + H3O+
If a solution of .5 M carbonic acid is adjusted to a pH of 2.5, the primary form of
the buffer will be: - Answer H2CO3
Most non-polar residues are located on the interior of a protein fold, but are
occasionally found on surfaces where they can mediate protein interactions. The
molecular basis of a hypothetical infectious disease is that a bacterial protein interacts
with a human protein by sharing a non-polar surface. Your goal as a researcher is to find
a way to disrupt this interaction. Which of the following surface mutations are most
likely to disrupt the protein interaction? - Answer leucine-->glutamine
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller KenAli. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for $13.49. You're not tied to anything after your purchase.
Can Stuvia be trusted?
4.6 stars on Google & Trustpilot (+1000 reviews)
78252 documents were sold in the last 30 days
Founded in 2010, the go-to place to buy study notes for 14 years now