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AAMC Test 3 questions and answers graded A+ 2024/2025

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AAMC Test 3 questions and answers graded A+ 2024/2025

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  • September 20, 2024
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AAMC Test 3

For a thermodynamic mixture of isomeric merchandise - ANSthe relative mole ratio of products
is without delay related to the relative balance of those merchandise

#2. What may be inferred from the outcomes of scheme A about the relative thermodynamic
stabilities of Compounds 4a and 4b

A. Compound 4a is much less stable than Compound 4b.
B. They are similarly solid.
C. Nothing can be inferred about relative thermodynamic stabilities.
D. Compound 4a is extra strong than Compound 4b. - ANSCompound 4a is greater stable than
4b

The image indicates that 4a is produced 60% and 4b forty%.
--So 4a may be more strong some of the thermodynamic products

#three. Which of the following compounds is most probably to be a main product in step 2 if the
aldol condensation is NOT followed by using a dehydration reaction? - ANSAns in image

--coz if there is no dehydration, then the OH might be present in place of the double bond

#four. Compound X is proven below.(photo)

If compound 2 is changed with compound X, what's going to be the shape of the final product in
steps 1 and a pair of? (Note: anticipate that the yields of steps 1 and 2 aren't suffering from
substitution) - ANSAns in image

--coz that is the made from Michael addition observed through intramolecular aldol
condensation (Robinson annulation)

#five. What is the total quantity of charge and energy, respectively, that the capacitor will store if
it's far connected to the battery at the railcar? - ANS1.20C and seven.20J

C=Q/V
Energy stored via a capacitor = Ue = (1//2)CV^2 = (half of)QV = (1/2)Q^2V

Given
V= 12V
C = a hundred x 10^-three F

Q = VC = (12)(one hundred x 10^-three) = 1.20 C

,Ue = (half)QV = (half of)(1.20)(12) = 7.20J

#6. Suppose that the railcar passes by a horn that is emitting a valid with a frequency f. Which
of the following describes f' that the man or woman at the railcar hears? - ANSf' > f earlier than
passing the horn, f' < f after passing it

Due to doppler effect, the frequency that the person on the railcar hears before passing the horn
is larger than the actual frequency of the sound emitted, while the person hears a frequency
lower than the actual frequency after passing the horn

--Before passing the horn, the object(rail car) is coming closer to the source (horn) so f'>f
--After passing the horn, the object(railcar) is transferring away from the supply (horn) so f<f'

Doppler effect - ANSThe apparent frequency (f') of the source is increased as the source
approaches the observer, and is decreased as the sources leaves the observer

f' = ((V+_ Vo)/(V-+Vs))f

#7. A railcar has a decelerating force of 1000 N. If no braking occurs, a total of how much power
would be required to keep the railcar moving at 40 m/s?

A. 16 kW
B. 40 kW
C. 600 kW
D. 800 kW - ANSPower = work done/ time
Work done = Fd
v= d/t --> d =vt

W= Fd --> Fvt
P = Fv = (1000N)(forty) = 40000 W = 40 kW

There are lot of pressure values given inside the passage however we use 1000N coz the
power required must in shape the paintings done via the friction pressure that tends to gradual
down the railcar

#10. Raadioactive tritium (3H) labeleed guanine has been used to degree the rate of
biochemical approaches that contain its building or incorporation

Given that water is the solvent for this type of experiment, what is the high-quality web page for
tritum labeling? - ANSI

Because the great website for tritium labeling would now not exchange the tritium ions for
protons in water. All of the N-H web sites (II-IV) could with no trouble change tritium protons due

, to their lone pair-facilitating protonation and subsequent tritium trade with water, however the
C-H web site (I), missing a lone pair, would retain its tritium label

#eight. If a generator-brake system alone had been engaged whilst the railcar became shifting,
which of the following graphs would most as it should be represent the following velocity of the
railcar? - ANSAns Image-->

Coz the velocity of the auto decreases in time such that the decelerating force declines linearly
with speed, in keeping with the passage. Because the decelerating force is without delay
proportional to the deceleration acceleration, it follows that the decelerating acceleration itself
declines linearly with speed. Finally, due to the fact the decelerating acceleration is the charge
of change of speed, or the slope of the velocity vs. Time graph, then the slope of the graph
ought to lower in time

#9. The relative thermodynamic stability of isomeric natural compounds can be inferred from
which of the following forms of experimental statistics?

A. Boiling factors
B. UV-seen absorption spectra
C. Mass spectroscopic fragmentation patterns
D. Heats of combustion - ANSD. Heats of combustion

The relative thermodynamic stability of isomers may be determined primarily based on the
amount of heat produced while the compounds are combusted; much less heat, more balance

#14. The electricity of activation for the response described within the passage is given by
means of the power of: - ANSThe activated complicated minus the strength of the reactants

The activation energy for the response presents the minimum energy barrier essential to be
conquer by the reactants on the route to merchandise

#sixteen. What kind of response is occurring among I2 and Zn? - ANSOxidation-discount

due to the fact each Zn and I2 exchange oxidation states in the course of the response

#18. What is the period of the voltage supply that operates the plasma pencil? - ANS1000ns

Because the period of a time-various sign is the shortest repitition time. According to fig 2, each
pulse is on for 500ns, then off for 500ns. Thus the time among consecutive pulse is 500ns +
500ns = 1000ns

#19. What is the most electricity of the UV photons generated by this plasma pencil? (Note:
speed of mild is c = 3.Zero x 10^8 m/s; Planck's steady is h = 6.Sixty three x 10^-34 J.S)
lamda = 2 hundred-300n - ANSE=hf = hc/lamda

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