. Calculate the tubing compliance (CT) when the measured volume is 150 mL and the static
pressure is 53 cm H2O.
a. 0.003 mL/cm H2O
b. 0.35 cm H2O/mL
c. 2.8 mL/cm H2O
d. 7.95cm H2O/mL
→ -:- C 2.8 mL/cm H2O
→ Calculate tubing compliance (CT) by dividing measured volume by measured static ...
Best Grades | Must Pass | Latest Update | Correct Answers | 2024/2025
RSCR242 - Exam 2 Pilbeam CH6-
Questions and Correct Answers | Latest
Update
1. Calculate the tubing compliance (CT) when the measured volume is 150 mL and the static
pressure is 53 cm H2O.
a. 0.003 mL/cm H2O
b. 0.35 cm H2O/mL
c. 2.8 mL/cm H2O
d. 7.95cm H2O/mL
→ -:- C 2.8 mL/cm H2O
→ Calculate tubing compliance (CT) by dividing measured volume by measured static
pressure.
2. When initially setting up a ventilator the plateau pressure (PPlateau) is measured at 47 cm
H2O with a set volume of 100 mL. After applying the ventilator to the patient, the average
peak pressure reached during volume delivery is 28 cm H2O. How much volume is lost in the
ventilator tubing?
a. 13 mL
b. 60 mL
c. 147 mL
d. 168 mL
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→ -:- B 60 mL
Calculate tubing compliance (CT) by dividing measured volume by measured static pressure.
The amount of volume lost to the circuit equals the pressure reached during a tidal volume (VT)
delivery multiplied by the CT factor.
3. A 90kg patient was placed on a mechanical ventilator following a major thoracic surgery.
A square flow-generating volume ventilator was used with the following settings: peak flow =
60L/min, f=15, sensitivity = -1 cmH2O, FI2 = 0.4, and expiratory time = 3 seconds. What
was the delivered VT for this patient?
A. 600 mL
B. 800 mL
C. 900 mL
D. 1000 mL
→ -:- D. 1000 mL
4. A 31 year old male patient has a body surface area of 2.0 m2 and an IBW of 180lbs
(82kgs). Body temperature is 37° C. He is still under the effects of anesthesia following
surgery on his leg. He has no history of lung disease. What minute ventilation would be
appropriate as an initial setting?
a. 6 L/min
b. 7 L/min
c. 8 L/min
d. 9 L/min
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, Best Grades | Must Pass | Latest Update | Correct Answers | 2024/2025
→ -:- C. 8 L/min
5. Calculate the average tidal volume for a patient who has a minute ventilation of 10 L/min
with a respiratory rate (RR) of 12 bpm.
a. 120 mL
b. 833 mL
c. 1000 mL
d. 1200 mL
→ -:- B. 833 mL, Vt = Ve/f, 10/12
6. Calculate the inspiratory time (TI) when a ventilator is set at a tidal volume (VT) of 500 mL
and a constant flow rate of 30 L/min.
a. 0.6 second
b. 1 second
c. 1.5 seconds
d. 1.7 seconds
→ -:- B 1 second
TI = VT/VE (convert L/min to L/sec)
7. Calculate the inspiratory to expiratory (I:E) ratio when the inspiratory time is 0.5 seconds
and the respiratory rate is 30 bpm.
a. 1:3
b. 1:4
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