Chemistry 210
Final, fall 2023
Questions and
Complete Solutions
Graded A+
Denning [Date] [Course title]
,C - Answer: The electron configuration of indium, In, is ______.
B - Answer: In general, atomic radii _____.
A) increase from left to right in a period and increase down a group.
B) decrease from left to right in a period and increase down a group.
C) increase from left to right in a period and decrease down a group.
D) do not change across a period or a group.
E) decrease from left to right and decrease down a group.
D.
g x 1mo/mm x 6.022x10^23/1 mol x #of na atoms - Answer: Calculate the number of sodium atoms in
9.28 g of sodium carbonate, Na2CO3. The molar mass of Na2CO3 is 105.99 g/mol.
A) 1.75 × 10-1 Na atoms
B) 5.27 × 1022 Na atoms
C) 1.58 × 1023 Na atoms
D) 1.05 × 1023 Na atoms
E) 8.76 × 10-2 Na atoms
C - Answer: Which of the following statements about quantum numbers is FALSE?
A) The principal quantum number (n) describes the size of an orbital.
B) The angular momentum quantum number (ℓ) describes the shape of an orbital.
C) The magnetic quantum number (mℓ) describes the direction of spin of an electron.
D) An electron in an atom can be uniquely identified by four quantum numbers (n, ℓ, mℓ, ms).
E= first ionization energy
,2nd= X+(g) >> X3+(g) + e-
3rd= X2+(g) >> X3+(g) + e- - Answer: Which one of the following equations correctly represents the
process relating to the first ionization energy of X?
A) X(s) ⟶ X+(g) + e-
B) X2(g) ⟶ X+(g) + X-(g)
C) X(g) + e- ⟶ X-(g)
D) X-(g) ⟶ X(g) + e-
E) X(g) ⟶ X+(g) + e-
C - Answer: Which of the following drawings represents a potassium cation, K+ ?
C
E= energy h=6.63x10^-34 J.s. = planks constant
E=hU
c=wavelengthU = speed of light
E= hc/wavelength - Answer: Calculate the energy of a photon of light that has a wavelength of 453 nm.
A) 6.62 × 1014 J
B) 2.28 × 1018 J
C) 4.39 × 10-19 J
D) 9.00 × 10-32 J
E) 4.53 × 10-7 J
C
same denominator
different numerator - Answer: Which of the following represent isotopes ?
, E
(mass 1 x percentx100 1) + (mass 2 x percentx100 2)= average atomic mass
(120.904 amu x 0.5730) + (X x (1 - 0.5730))= 121.757 amu
69.278 amu + 0.427 X = 121.757 amu
X=122.9 amu - Answer: Element X has two naturally occurring isotopes and an average atomic mass of
121.757 amu. One of the isotopes has a mass of 120.904 amu and a percent abundance of 57.30%.
What is the mass of the other isotope ?
A) 122.4 amu
B) 121.8 amu
C) 121.2 amu
D) 122.6 amu
E) 122.9 amu
A
50 - 4 - Answer: Which of the following species has 46 electrons ?
B
denominator = protons
numerator - denominator = neutrons
denominator +- charge - Answer: How many protons, neutrons, and electrons are in
A) 24 protons, 27 electrons, 32 neutrons
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