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BIOS 255 Exam-Questions and Answers Rated A+

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BIOS 255 Exam-Questions and Answers Rated A+

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  • September 23, 2024
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  • Exam (elaborations)
  • Questions & answers
  • BIOS 255
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BIOS 255 Exam-Questions and Answers Rated A+


The purpose of adding a trace amount of histidine and biotin: Correct Ans-Small amount of


histidine is added to allow a limited amount of growth, during which time mutations can


arise; biotin is needed as well because the his mutation has disabled the biotin synthesis


pathway.




Which of the 7 strains was sensitive to Glyphosate? Correct Ans-Proteus vulgaris




Can you do a dilution problem? Correct Ans-C1V1=C2V2


V1 = volume of a stock solution needed to make new solution


C1= concentration of stock solution


V2 = final volume of new solution


C2 = final concentration of new solution


Example: Make 5 mL of a .25 M solution from a 1 M solution


→ V1(.25 M)=(1 M)(5 mL)

, BIOS 255 Exam-Questions and Answers Rated A+
→ V1 = [(1 M)(5 mL)] / (.25 M)


→ V1 = 1.25 mL




Be able to determine oxygen requirements of microbes grown in fluid thioglycollate.


Correct Ans-Obligate aerobe, obligate anaerobe, microaerophile, facultative anaerobe,


aerotolerant anaerobe - what is the difference between them? • Obligate aerobe must have


O2 for growth because O2 us used as the terminal electron acceptor for oxidative


phosphorylation


Obligate anaerobe cannot grow in the presence of O2 and may be killed by trace amonts of


O2


Microaerophile need a small amount of O2 for growth but too much O2 will kill them. A


subsetset can tolerate O2 but they do not use it.


Facultative anaerobe grow best when O2 is available, but can also grow, though not was well,


when O2 Is not present.


Aerotolerant anaerobe same as facultative

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