Solutions for Business Statistics Communicating with Numbers, 5th Edition by Jaggia (All Chapters included)
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Course
Biostatistics
Institution
Biostatistics
Complete Solutions Manual for Business Statistics Communicating with Numbers, 5th Edition by Sanjiv Jaggia, Alison Kelly ; ISBN13: 9781265035983....(Full Chapters included and organized in reverse order from Chapter 20 to 1)...1. Data and Data Preparation
2. Tabular and Graphical Methods
3. Num...
Business Statistics Communicating
with Numbers, 5th Edition
by Sanjiv Jaggia
Complete Chapter Solutions Manual
are included (Ch 1 to 20)
** Immediate Download
** Swift Response
** All Chapters included
,Table of Contents are given below
1. Data and Data Preparation
2. Tabular and Graphical Methods
3. Numerical Descriptive Measures
7. Sampling and Sampling Distributions
8. Interval Estimation
9. Hypothesis Testing
10. Statistical Inference Concerning Two Populations
11. Statistical Inference Concerning Variance
12. Chi-Square Tests
13. Analysis of Variance
14. Regression Analysis
15. Inference with Regression Models
16. Regression Models for Nonlinear Relationships
17. Regression Models with Dummy Variables
18. Forecasting with Time Series Data
19. Returns, Index Numbers, and Inflation
20. Nonparametric Tests
,Solutions Manual organized in reverse order, with the last chapter
displayed first, to ensure that all chapters are included in this
document. (Complete Chapters included Ch20-1)
c. Since the p-value= 0.029 < 0.05 = 𝛼, we reject 𝐻0 . At the 5% significance level,
we conclude that the median is less than 10.
4.
a. Given 𝑇 = 𝑇 + = 265 and T is assumed normally distributed, we calculate
𝑛(𝑛+1) 30(30+1) 𝑛(𝑛+1)(2𝑛+1) 30×(30+1)(2×30+1)
𝜇𝑇 = = = 232.50 and 𝜎𝑇 = √ =√ =
4 4 24 24
𝑇−𝜇𝑇 265−232.50
48.6184. Therefore, 𝑧 = = = 0.6685.
𝜎𝑇 48.6184
b. The p-value =𝑃(𝑍 ≥ 0.6685) = 0.2519
In Excel: =1-NORM.DIST(0.6685, 0, 1, TRUE)
In R: 1-pnorm(0.6685, 0, 1, lower.tail=TRUE)
c. Because the p-value= 0.2519 > 𝛼 = 0.05, we do not reject 𝐻0 . Thus, at the 5%
significance level, we cannot conclude that the median is greater than 150.
5.
a. 𝐻0 : 𝑚 = 100; 𝐻𝐴 : 𝑚 ≠ 100
20-2
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