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ASU BIO 340 Exam 3 Latest Update Actual Exam from Credible Sources with 90 Questions and 100% Verified Correct Answers Guaranteed A+ Verified by Professor
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ASU BIO 340 Exam 3 Latest Update Actual Exam from Credible Sources with 90 Questions and 100% Verified Correct Answers Guaranteed A+ Verified by Professor

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  • October 3, 2024
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  • 2024/2025
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ASU BIO 340 Exam 3 Latest Update 2024-2025
Actual Exam from Credible Sources with 90
Questions and 100% Verified Correct Answers
Guaranteed A+ Verified by Professor

: What type of mutation is seen here? Wild type: 5'-TAC AAA ATA CAG CGG-3'
Mutation: 5'-TAC AAG ATA CAG CGG-3' A. Transversion B. Deletion C. Transition D.
Insertion - CORRECT ANSWER: C Explanation: A is a purine and G is a purine, so this
is a transition


A bacterium is unable to transport lactose into the cell to be broken down. Which gene
is likely mutated in this bacterium?
A. lacZ B. lacY C. lacI D. lacP E. lacO - CORRECT ANSWER: B Explanation: If you
can't transport lactose, then it means permease isn't working. So lacY is likely mutated
since that is the gene that encodes permease.


A bacterium needs to make a certain lipid that it cannot obtain from its environment.
That same lipid is involved in regulating the expression of the enzymes that make it.
Which of the following is the most likely regulatory function of the lipid?
A. Effector B. Activator C. Inducer D. Co-repressor E. Operator - CORRECT ANSWER:
D Explanation: If you have that lipid, you would want it to not make any more. So, if you
have the lipid in the cell, you would want to turn off the transcription, so it would likely be
involved in negative regulation. Effectors and activators are both involved in positive
regulation. An inducer is under negative regulation but its job is to turn on transcription.
A co-repressor will only turn the gene off if there is a signal the cell can sense. Operator
is a piece of DNA.


Babies in a hospital were switched at birth. Identify each mother's baby. A. Mother 1 and
baby 2, mother 2 and baby 1 B. Mother 1 and baby 3, mother 2 and baby 2 C. Mother 1
and baby 2, mother 2 and baby 3 D. Mother 1 and baby 1, mother 2 and baby 3 -
CORRECT ANSWER: C Explanation: Mother and baby must share at least one VNTR
allele (band on the gel) (we are diploid, so each baby will have one allele from each
parent, and therefore must share at least one allele with each parent). Mother 1 and
Baby 2 share the allele at size 1. Mother 2 and Baby 3 share an allele at size 3.

, Can the resulting ligated sequences be cut by BamHI A. Yes B. No - CORRECT
ANSWER: B Explanation: The resulting ligated sequence no longer has the recognition
sequence for BamHI. So the enzyme can no longer cut it


Can the sticky ends produced by BamHI and BcII be ligated together?
A. Yes B. No - CORRECT ANSWER: A Explanation: The overhangs left by each
enzyme are complementary to each other


DNA polymerase III adds nucleotides __________. A. To the 3' end of the RNA primer
B. To the 5' end of the RNA primer C. In the place of the primer RNA after it is removed
D. To both ends of the RNA primer E. To internal sites in the DNA template - CORRECT
ANSWER: A. to the 3' end of the RNA primer


For a gene under negative control, which of the following would you expect to find
bound to the repressor if there is active transcription? A. Repressor B. Corepressor C.
Inducer D. Effector E. Inhibitor - CORRECT ANSWER: C Explanation: In negative
regulation, there are repressors (affected by correpressors and inducers). If there were
a corepressor, the repressor would successfully bind to the operator and prevent
transcription. Inducers, however, prevent the binding of the repressor - thus causing a
prevention of it doing its job, and allowing transcription.


For a gene under positive control, which of the following would prevent transcription?
A. Repressor B. Corepressor C. Inducer D. Effector E. Inhibitor - CORRECT ANSWER:
E Explanation: Positive regulation includes activators (affected by effectors and
inhibitors); inhibitors prevent activator from binding to DNA, thus preventing
transcription.


Given the linear DNA molecule shown below, how many fragments would you expect if
it was cut with BamHI and BcII?
A. 1 B. 2 C. 3 D. 4 E. 5 - CORRECT ANSWER: C Explanation: BamHI and BclI will cut
the double-strand only once each, having three pieces of double-stranded DNA as a
product.

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