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DISCRETE MATH EXAMINATION QUESTIONS WITH COMPLETE SOLUTIONS GRADED A+ $11.49   Add to cart

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DISCRETE MATH EXAMINATION QUESTIONS WITH COMPLETE SOLUTIONS GRADED A+

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DISCRETE MATH EXAMINATION QUESTIONS WITH COMPLETE SOLUTIONS GRADED A+ what is predicate? - Answer-The predicate tells what the subject is or does. the domain is? - Answer-all values that can be substituted to predicate P(x) => Q(x) - Answer-every element in truth set of P is in the truth set ...

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  • October 22, 2024
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  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • DISCRETE MATH
  • DISCRETE MATH
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DISCRETE MATH EXAMINATION
QUESTIONS WITH COMPLETE
SOLUTIONS GRADED A+
what is predicate? - Answer-The predicate tells what the subject is or does.

the domain is? - Answer-all values that can be substituted to predicate

P(x) => Q(x) - Answer-every element in truth set of P is in the truth set of Q

P(x) <=> Q(x) - Answer-truth sets are identical

Negation of Quantifiers - Answer-quantifier and predicate negates

A is subset of B - Answer-A ⊆ B, every element in A is in B

Proper subset - Answer-If A ⊆ B, and There is at least one element in B that is not in A

Proofing the subset relation - Answer-Take an arbitrary element in subset

Set Equality - Answer-A and B equals, A=B, if every element of A is in B, abd B in A

A ⊆ B and B ⊆ A

Set Union - Answer-A U B, is the result set that contains elements that at least in one
sets

set intersection - Answer-A ∩ B, elements that are both in A and B

Set difference - Answer-A - B, is the set of elements in A that not in B

Set compliment - Answer-A^c, all elementa outside of A

Disjointed sets - Answer-if set A and B have no common elements

mutually disjoint - Answer-All collection of sets have no common elements

Partition of set A of collection of sets - Answer-A is union of all Ai, and sets are mutually
disjointed

Power set - Answer-Power set of A, is a set of all subsets of A and empty set

, Cartesian product of sets ordered - Answer-A x B, take one element in A, and make
combination with every element in B, then go to next element in A

A ∩ B ⊆ A - Answer-union, intersection and difference first, then inclusionA

⊆ A 𝖴 B - Answer-inclusion


transitivity of sets - Answer-A ⊆ B and B ⊆ C, then A⊆C

compliment law - Answer-(A^c)^c = A

de Morgan for sets - Answer-(A 𝖴 B)^c = A^c ∩ B^c

Set difference law - Answer-A - B = A ∩ B^c

f: X -> Y - Answer-X domain, Y codomain, there is only single arrow from X to Y. But to
the element in Y, can go two separate arrows

identity function - Answer-Ix = x. each element maps to itself

inverse image of function - Answer-F(1) = 4, F^(-1)(4) = 1

one-to-one function - Answer-if F(x1) = F(x2), then x1 = x2. Arrow points from element X
to only one element Y. Every element in X should map to Y. can be free elements in Y

Onto functions - Answer-given element in Y, it's possible to find an element that maps to
Y. Every element in Y should have element/s in X that maps to it.

bijection - Answer-if both one-to-one and onto

composition function - Answer-(g ° f)(x) = g(f(x))

composition and inverse - Answer-f ° f^-1 = Ix

Composition one-to-one/onto - Answer-then relation is one-to-one/onto



what is a statement? - Answer-is a sentence that is true or false but not both

p but q - Answer-p and q

negation - Answer-~p (not p)

conjunction - Answer-p 𝖠 q

disjunction - Answer-p ∨ q

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