100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Che 505 Final Exam Part 1 (Oral) With Complete Solutions Latest Update $14.49   Add to cart

Exam (elaborations)

Che 505 Final Exam Part 1 (Oral) With Complete Solutions Latest Update

 3 views  0 purchase

Che 505 Final Exam Part 1 (Oral) With Complete Solutions Latest Update

Preview 3 out of 29  pages

  • October 30, 2024
  • 29
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
All documents for this subject (5)
avatar-seller
Schoolflix
Solution 2024/2025
Pepper

Che 505 Final Exam Part 1 (Oral) With
Complete Solutions Latest Update

Number of equations vs. number of unknowns



square systems/matrices have ANS✔✔ the same number of equations as
unknowns (m=n)



Cramers Rule ANS✔✔ tells if there is a unique and existing solution



If we want to solve Ax=b, find the kth element of the vector x by dividing
the determinant of A with the kth column replaced by vector b by the
determinant of A



When is a matrix singular, and what does singularity imply about the
solution ANS✔✔ det(A)=0



as long as a is not singular, a solution to Ax=b exists and is unique (1
solution)



Why is using the cramers rule impracticle ANS✔✔ scales as n factorial:
"combinatorial scaling"



slow alogorithims, avoid if possible

, Solution 2024/2025
Pepper
traingular matrices ANS✔✔ upper: every element below the main diagonal
is zero, nonzero elements on and above the main diagonal



lower: every element above the main diagonal is zero, nonzero elements on
and below the main diagonal



what is the determinant of a triangular matrix ANS✔✔ the product of all
terms on the main diagonal



how to solve Ax=b using a triangular matrix ANS✔✔ upper traingular matrix:
back solving

lower traingular matrix: forward solving



How can a matrix be transformed into a triangular matrix? ANS✔✔ Guassian
Elimination



Gaussian elimination ANS✔✔ main goal: get every value below the main
diagonal equal to zero using elemenentary row operation: multiply row by a
scalar and add rows together



generalized steps: every column from k=1 to n-1

every row from j=k+1 to n

multiply row k by -ajk/akk

add result to row j



augmented matrix ANS✔✔ add vector b as a new column in A

, Solution 2024/2025
Pepper
can do gaussian elimination of augmented matrix



Scaling of gaussian elimination ANS✔✔ consider the number of
multiplication and addition operations



O(n^3) polynomial scaling--fast algorithm



much better than combinatorial scaling (cramers rule)



How does guassian elimination affect the determinant of the matrix ANS✔✔
it doesnt: elementary row operations dont change the determinant



the determinant equals the determinant of the original matrix



pivoting ANS✔✔ using row swaps to ensure we can proceed with gaussian
elimination

swap with any row below where we currently are such that the new diagonal
term after swapping is nonzero



necessary when the diagonal term is exactly zero

useful when diagonal term is very small but nonzero (dividing by small
number can cause roundoff error)



swap row = partial pivoting

swap columns = full pivoting, the order of the x's change

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller Schoolflix. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $14.49. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

72042 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$14.49
  • (0)
  Add to cart