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STA 2023 Final Exam Questions with Complete Solutions Graded A+
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STA 2023 Final Exam Questions with Complete Solutions Graded A+
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STA 2023 Final ExamQuestions and Complete
Solutions Graded A+
Chapter 3: Compute the 25% trimmed mean given the data 72, 83, 87, 93. - Answer: n = 4. 25% = 1/4.
trim 72 and 93. 83 and 87 remaining. (83 + 87) = 170/2 = 85.
Compute the weighted average for the following four test grades and respective
weights. Grades: 72, 87, 83, 93; Weights: 1, 2, 3, 4. - Answer: [(72x1) + (87x2) + (83x3) + (93x4)]/1 + 2 + 3
+ 4 = 72 +174 + 249 + = = 77.4
Data is skewed to the left when the mean is to the _________ of the median. - Answer: left
Data is skewed to the right when the mean is to the _________ of the median. - Answer: right
One of the principles of experimental design states that a good experiment has a
comparative group by which we can compare the test group to a __________. - Answer: control group
principles of experiment design states that a good sample must be selected
at - Answer: randomization, replication, and local control
One of the principles of experimental design states that a good experiment must be
able to be - Answer:
One of the principles of experimental design states that a good sample must be large
enough; that is, for means a sample size of at least - Answer:
, One of the principles of experimental design states that a good sample must be large
enough; that is, for proportions a sample must consist of at least _____ in each cell. - Answer:
The first principle of probability states that the probability of the sample space is ______. - Answer: 1
The second principle of probability states that the probability of any event is between
____ and ____. - Answer: 0, 1
The third principle of probability states that if the events are mutually exclusive and in
__________ form the sample space, then the sum of the probability of the events is one - Answer: union
Given 𝑷(𝑬) = 𝟎. 𝟑𝟖, then 𝑷(𝑬̅) = ___________. - Answer: 0.62 (1 - 0.38)
Let 𝒏(𝑬) be the number of outcomes in an event 𝐸. Given 𝒏(𝑬) = 𝟐𝟏 and 𝑷(𝑬) = 𝟎. 𝟕,
then 𝒏(𝑬̅) = ___________. - Answer: n(E) * P(E) = 21 * 0.7 = 15. 21 * (1 - 0.7) = 21 * 0.3 = 6. 15 - 6 = 9 =
𝒏(𝑬̅)
Given n(E) 21 and P(E) = 0.7, then Odds(E) = _______. - Answer: Odds(E) = P(E)/P(𝑬̅) = 0.7/0.3 = 7:3
Given four women and five men, what is the probability of two women (W) and one man (M)
are selected to form a three-member committee? P(2W and 1M) = ? - Answer: (4C2 x 5C1)/(9C3) = (6 x
5) / 84 = 30/84 = 0.3571
Given A and B are dependent, then P(A n B) = ? - Answer:
Given A and B are independent, then P(A | B) = ? - Answer:
Given A and B are independent, then P(A ∩ B) = - Answer:
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