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CALC BC EXAM.2024/2025 WITH 100% ACCURATE SOLUTIONS $16.49   Add to cart

Exam (elaborations)

CALC BC EXAM.2024/2025 WITH 100% ACCURATE SOLUTIONS

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  • Course
  • CALC BC
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  • CALC BC

CALC BC EXAM.2024/2025 WITH 100% ACCURATE SOLUTIONS

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  • November 5, 2024
  • 9
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • CALC BC
  • CALC BC
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YANCHY
CALC BC EXAM.2024/2025 WITH 100%
ACCURATE SOLUTIONS


If f(x)=cos^2(3x-5)


f'(x)= - Answer -6sin(3x-5)cos(3x-5)


∫1/t√t dt= - Answer -2t^(-1/2) + c


If f(x)= (5-x)/(x^3+2)


f'(x)= - Answer (2x^3-15x^2-2)/(x^3+2)^2


The position of a particle moving in the xy-plane is given by the vector {4t^3,y(2t)},
where y is a twice-differeniable function of t.


At time t=1/2, what is the acceleration vector of the particle? - Answer {12,4y"(1)}


To what number does the series


E (-e/pi)^k converge? - Answer π/(π+e)


Look at graph on #6


Which of the following is true? - Answer lim as x->a of f(x) ≠ f(a)


If ∫4 -10 g(x)=-3

, and ∫4 6 g(x)=5


then ∫-10 6 g(x)= - Answer 8


The length of the curve y=sin(3x) from x=0 to x=π/6 is given by - Answer ∫0 π/6
√1+9cos^2(3x)


The slope of the line tangent to the graph of y=xe^x
at x=ln2 is - Answer 2ln2 + 2


Let y=f(x) be the solution to the differential equation dy/dx= x-y with initial condition
f(2)=8. What is the approximation for f(3) obtained by using Euyler's method with two
steps of equal length, starting at x=2? - Answer 15/4


If x^2+xy-3y=3, then at the point (2,1)


dy/dx= - Answer 5


~(3x+1)/(x^2-4x+3)= - Answer 5ln[x-3] - 2ln[x-1] + c


Which of the following is a slope field for


dy/dx= x^2+y^2? - Answer look for graph where slope increases as y increases


If f(x)=3x^2+2x


f'(x)= - Answer lim as h->0 (3(x+h)^2+2(x+h))-(3x^2+2x) / h


Look at graphs for #15.

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