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CHEM 120 WEEK 4 EXAM REVIEW QUESTIONS AND ACCURATE ANSWERS RATED A.
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CHEM 120 WEEK 4 EXAM REVIEW QUESTIONS AND ACCURATE ANSWERS RATED A.
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CHEM 120 WEEK 4 EXAM REVIEWQUESTIONS AND ACCURATE ANSWERS
RATED A.
A chemist dissolves 24 grams of CaCl₂ (molecular mass 110.98 g/mol) in
water to make a solution with a total volume of 360 mL. What is the molarity
of this solution?
• Correct Answer: 0.6 M
• Explanation: Molarity is calculated as moles of solute divided by liters of
solution. First, convert grams to moles (24 g / 110.98 g/mol ≈ 0.216
moles) and volume to liters (360 mL = 0.36 L). Then, divide moles by
liters (0.216 moles / 0.36 L = 0.6 M).
What formula would you use to prepare a dilute solution from a
concentrated solution?
• Correct Answer: C₁V₁ = C₂V₂
• Explanation: This formula (where C = concentration and V = volume)
helps calculate how much of a concentrated solution is needed to
prepare a dilute solution.
You are preparing a solution from 750 L of a 3.0 M NaCl solution. How many
liters of a 1.5 M NaCl solution could you produce by diluting the original
solution?
• Correct Answer: 1500 L
• Explanation: Using C₁V₁ = C₂V₂, substitute the values (3.0 M * 750 L =
1.5 M * V₂). Solving for V₂ gives 1500 L.
, How many ions would you expect MgBr₂ to dissociate into in water?
• Correct Answer: 3
• Explanation: MgBr₂ dissociates into one Mg²⁺ ion and two Br⁻ ions,
totaling three ions in solution.
A chemist dissolves FeBr₃ in water to make a 2.0 M solution. What is the
osmolarity of this solution?
• Correct Answer: 8.0 Osm/L
• Explanation: FeBr₃ dissociates into four particles (1 Fe³⁺ and 3 Br⁻ ions),
so osmolarity = 2.0 M * 4 = 8.0 Osm/L.
Select all that apply. According to the Kinetic Molecular Theory of Gases
(KMT), which statements are assumed for gas particles?
• Correct Answer:
o There is no attraction between the particles of the gas.
o Any collision between gas molecules is perfectly elastic.
o Gas particles are in random, continuous motion.
• Explanation: KMT assumes no intermolecular forces, elastic collisions,
and constant, random motion for gas particles.
A sample of gas is cooled at constant pressure. What would you expect the
volume of the gas to do?
• Correct Answer: Decrease
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