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CHEM 120/103 MODULES EXAM 2025 FINEST MODULE 1-6 PRE PREDICTOR EXAM 100% GUARANTEED PASS $12.00   Add to cart

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CHEM 120/103 MODULES EXAM 2025 FINEST MODULE 1-6 PRE PREDICTOR EXAM 100% GUARANTEED PASS

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CHEM 120/103 MODULES EXAM 2025 FINEST MODULE 1-6 PRE PREDICTOR EXAM 100% GUARANTEED PASS

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  • November 12, 2024
  • 38
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
  • CHEM 120/103 MODULES
  • CHEM 120/103 MODULES
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CHEM 120/103 MODULES EXAM 2025 FINEST MODULE 1-6
PRE PREDICTOR EXAM 100% GUARANTEED PASS


MODULE 1 EXAM

Question 1

1. Convert 845.3 to exponential form and explain your answer.

2. Convert 3.21 x 10-5 to ordinary form and explain your answer.




1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places

= 8.453 x 102

2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 places = 0.0000321



Question 2



Using the following information, do the conversions shown below, showing all work:

1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts

1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints



kilo (= 1000) 1/100)



milli (= 1/1000) deci (= 1/10)



centi (=




CHEM 120/103 MODULES EXAM

, 1. 24.6 grams = ? kg




2. 6.3 ft = ? inches




1. 24.6 grams x 1 kg / 1000 g = 0.0246 kg

2. 6.3 ft x 12 in / 1 ft = 75.6 inches



please always use the correct units in your final answer



Question 3



Do the conversions shown below, showing all work:

1. 28oC = ? oK 2. 158oF = ? oC 3. 343oK = ? oF

1. 28oC + 273 = 301 oK oC → oK (make larger)

+273

2. 158oF - 32 ÷ 1.8 = 70 oC oF → oC (make smaller)

-32 ÷1.8

3. 343oK - 273 = 70 oC x 1.8 + 32 = 158 oF oK → oC → oF



Question 4



Be sure to show the correct number of significant figures in each calculation.




1. Show the calculation of the mass of a 18.6 ml sample of freon with density of 1.49 g/ml

CHEM 120/103 MODULES EXAM

,2. Show the calculation of the density of crude oil if 26.3 g occupies 30.5 ml.



1. M = D x V = 1.49 x 18.6 = 27.7 g

2. D = M / V = 26..5 = 0.862 g/ml



Question 5



1. 3.0600 contains ? significant figures.

2. 0.0151 contains ? significant figures



3. 3.0600 ÷ 0.0151 = ? (give answer to correct number of significant figures)



1. 3.0600 contains 5 significant figures.

2. 0.0151 contains 3 significant figures.

3. 3.0600 ÷ 0.0151 = 202.649 = 203 (to 3 significant figures for 0.0151)



Question 6

Classify each of the following as an element, compound, solution or heterogeneous mixture and explain
your answer.

1. Coca cola

2. Calcium

3. Chili



1. Coca cola - is not on periodic table (not element) - no element names (not compound)

appears to be one substance = Solution

2. Calcium - is on periodic table = Element

3. Chili - is not on periodic table (not element) - no element names (not compound)

appears as more than one substance (meat, beans,


CHEM 120/103 MODULES EXAM

, sauce) = Hetero Mix



Question 7



Classify each of the following as a chemical change or a physical change




1. Charcoal burns

2. Mixing cake batter with water



3. Baking the batter to a cake



1. Charcoal burns - burning always = chemical change

2. Mixing cake batter with water - mixing = physical change

3. Baking the batter to a cake - baking converts batter to new material = chemical change



Question 8



Show the full Nuclear symbol including any + or - charge (n), the atomic number (y), the mass number
(x) and the correct element symbol (Z) for each element for which the protons, neutrons and electrons
are shown - symbol should appear as follows: xZ +/- n




31 protons, 39 neutrons, 28 electrons



31 protons = Ga31, 39 neutrons = 70Ga31, 28 electrons = (+31 - 28 = +3)

= 70Ga +3



Question 9


CHEM 120/103 MODULES EXAM

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